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marta [7]
3 years ago
15

The right line is a 90° clockwise rotation of the left line about the origin. Click the 90° clockwise button. Are these lines th

e same? What does this mean about how a line changes when you rotate it?
Chemistry
1 answer:
inessss [21]3 years ago
7 0

Answer:

Switch the coordinates and change the sign of the second one by multiplying it by negative 1.

Explanation:

Here are some examples and a more general way to understand the problem.

Consider the point (1,1), a 90 degree rotation clockwise about the origin would move it into the 4th quadrant.

The new point is (1,-1) , similarly (-4,2)-> (2,4), (-4,3)-> (3,4)

We take a point p= (x,y) the the result of rotation p 90 clockwise about the orgin is a new point p'=(x',y')= (-y, x). .

In the case of p=(1,0) the new point is p'= (0, -1)

One can use a matrix where the first row is cos(a), sin(a) and the second row is

-sin(a) cos(a) for any clockwise rotation of a degrees about the origin.

If we let a=90 degrees we have

[0 1] as the first row and [-1 0] as the second row. So the matrix is:

|0 1|

|-1 0|

Call that matrix M

So a point p= (x,y) can be multiplied by M as follows Mp=p' where p' is the rotated point.

If p=(-4,2) then Mp

is M(-4,2) which after matrix multiplication means x'=0*-4+1*2=2 and y'=-1*-4+0*2=4

So p'=(2,4)

Try it with (1,0)

x'=1*0+0*1=0

y'=-1*1+0*1=-1

so p'=(0,-1) and (1,0)->(0,-1)

How about the point on the y axis (0,1), it should go to the point (1,0)

0*1+1*1=1 and -1*0+0*1 gives you the pont (1,0) ( we don't see the negative sign because -0 is just 0)

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azamat

Answer : The value of K_{sp} for BaCO_3 is 19.36\times 10^{-10}mole^2/L^2.

Solution : Given,

Solubility of BaCO_3 in water = 4.4\times 10^{-5}mole/L

The barium carbonate is insoluble in water, that means when we are adding water then the result is the formation of an equilibrium reaction between the dissolved ions and undissolved solid.

The equilibrium equation is,

                            BaCO_3\rightleftharpoons Ba^{2+}+CO^{2-}_3

Initially                   -                   0        0

At equilibrium       -                   s         s

The Solubility product will be equal to,

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K_{sp}=s\times s=s^2

[Ba^{2+}]=[CO^{2-}_3]=s=4.4\times 10^{-5}mole/L

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K_{sp}=(4.4\times 10^{-5}mole/L)^2=19.36\times 10^{-10}mole^2/L^2

Therefore, the value of K_{sp} for BaCO_3 is 19.36\times 10^{-10}mole^2/L^2.

3 0
3 years ago
What is a process of reacting an acid with a base until an equivalence point is reached
Brrunno [24]
TITRATION is the process of reaching equilibrium between acids and bases.
8 0
3 years ago
The pressure of a sample of helium in a 200. ml. container is 2.0 atm. If the 5 points
just olya [345]

The pressure of the gas = 40 atm

<h3>Further explanation</h3>

Given

200 ml container

P = 2 atm

final volume = 10 ml

Required

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Solution

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\tt \rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

Input the value :

P₂ = P₁V₁/V₂

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3 0
3 years ago
tate whether the following changes are physical or chemical for rancidipication fixation of water 2 tearing of paper 3 rusting o
damaskus [11]

Answer: Physical change : tearing of paper, fixing of wtaer

Chemical change:  rusting of iron ,  electrolysis of water​, Rancidification

Explanation:

Physical change is a change in which there is no rearrangement of atoms and thus no new substance is formed. There is only change in physical state of the substance.

Example:  tearing of paper, fixing of wtaer

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3 0
3 years ago
A laser produces 17.0 mW of light. In 4.00 hr , the laser emits 6.04×1020 photons. What is the wavelength of the laser?
Vlad [161]
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Solving for energy,
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Using the Planck's equation:

E = hc/λ
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4.053×10⁻¹⁹ J/photon = (6.626×10⁻³⁴ m²·kg/s)(3,00,000,000 m/s)/λ
λ = 4.9×10⁻⁷ m or 49 micrometers


5 0
3 years ago
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