The solution to the polynomial expression since the power of the variable is in the second degree is 6.29 × 10² cm
<h3>What is the power of a variable?</h3>
The power of a variable refers to the exponent of the variable and the highest power of a variable is the degree to which the variable is being raised. From the information given, the highest power of the variable is a polynomial.
Given that:
So, since the exponents are in the same power we are going to add them all together multiplied by their exponent.
i.e.
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The kinetic energy in the solid and liquid phases is the same. The kinetic energy of the substance's particles will depend on the volume of the substance. The particles have less kinetic energy in the liquid phase than they do in the gas phase. ... They vibrate so quickly that the particles ionize and become plasma.
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Answer:
The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).
Explanation:
The reaction between an acid and a base is called neutralization, forming a salt and water.
Salt is an ionic compound made up of an anion (positively charged ion) from the base and a cation (negatively charged ion) from the acid.
When an acid is neutralized, the amount of base added must equal the amount of acid initially present. This base quantity is said to be the equivalent quantity. In other words, at the equivalence point the stoichiometry of the reaction is exactly fulfilled (there are no limiting or excess reagents), therefore the numbers of moles of both will be in stoichiometric relationship. So:
V acid *M acid = V base *M base
where V represents the volume of solution and M the molar concentration of said solution.
In this case:
- V acid= 13.7 mL= 0.0137 L (being 1,000 mL= 1 L)
- M acid= 0.129 M
- V base= ?
- M base= 0.135 M
Replacing:
0.0137 L* 0.129 M= V base* 0.135 M
Solving:
V base=0.0131 L = 13.1 mL
<u><em>
The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).</em></u>
Answer:-
399 gram
Explanation:-
The balanced chemical equation for the reaction is
4Fe +3 O2 --> 2 Fe2O3
Atomic mass of Iron Fe is 55.845 gram
Molecular mass of Iron (III) Oxide Fe2O3 is
55.845 x 2 + 16 x 3 = 159.69 gram
From the balanced chemical equation,
4 Fe gives 2 Iron (III) oxide
∴ 4 x 55.845 grams of Fe gives 2 x 159.69 grams of Iron (III) Oxide.
279 grams of Fe gives (2 x 159.69) x 279 / ( 4 x 55.845)
= 399 gram
Answer:
Explanation:
Answer is B i got it right
