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3 years ago

A 1.0-gram sample of which element will uniformly fill a closed 2.0-liter container at STP?

Chemistry

2 answers:

Paladinen [302]3 years ago

8 0

Answer:

Carbon

Explanation:

To know this, let's write the ideal gas expression:

PV = nRT

As we are in STP, means that we have a pressure of 1 atm and 0 °C or 273.15 K. So, we have the volume which is 2 L, all we have to do is to calculate the moles of the substance, and then, the molecular weight with the given mass. The molecular weight that matches any of the option, would be the elemento that fullfill these conditions:

the moles (n):

n = PV/RT

n = 1 * 2 / (0.08206*273.15)

n = 0.089 moles

Now that we have the moles, let's calculate the molecular weight.

MM = m/n

MM = 1 / 0.089

MM = 11.24 g/mol

This molecular weight is very close to the molecular mass of the carbon (12 g/mol) . So the correct option is b, carbon.

Nesterboy [21]3 years ago

5 0

The answer will be C. Xenon

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How many mL of a 6 M NaOH stock solution is needed in order to prepare 500 mL of a 0.2 M NaOH solution?

WITCHER [35]

Answer:

The right answer is "16.67 mL".

Explanation:

Given:

Molarity of NaOH,

$M_1=6 \ M$

$M_2=0.2 \ M$

Volume of NaOH,

$V_1=V \ mL$

$V_2=500 \ mL$

As we know, the equation,

⇒ $M_1V_1=M_2V_2$

On putting the values, we get

⇒ $6\times V=0.2\times 500$

⇒ $6\times V=100$

⇒ $V=\frac{100}{6}$

⇒ $=16.67 \ mL$

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BARSIC [14]

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