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3 years ago

How many grams of CO2 will be produced from 39 grams of C3H8 and 11 grams of O2

Chemistry

1 answer:

Alexeev081 [22]3 years ago

4 0

Answer:

Equation: C3H8 + 5O2 = 3CO2 + 4H2O (already balanced)

a) If you start with 14.8 g of C3H8 and 3.44 g of O2, determine the limiting reagant

b) Determine the number of moles of carbon dioxide produced

c) Determine the number of grams of H2O produced

d) Determine the number of grams of excess reagant left

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Romashka-Z-Leto [24]

Answer:

Avogadro's number or Avogardro’s constant

Explanation:

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2 years ago

Mg + 2AgNO3 -> 2Ag + Mg(NO3)2

9966 [12]

Answer:

Explanation:

We'll assume there is an excess of silver nitrate, so that all 12.0 moles of the magnesium (Mg) will react.

The balanced equation tells us we'll obtain 2 moles of Ag for every 1 mole of magnesium, for a molar ratio of 2/1.

Starting with 12.00 moles Mg, we would therefore hope to find twice that, or 24.00 moles of Ag.

To convert to grams, find the molar mass of Ag from the periodic table.

Ag has a molar mass of 107.9 (to 4 sig figs) grams/mole.

(24.00 moles)*(107.9 grams/mole) = 2590 grams (4 sig figs)

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2 years ago

What patterns in the rock layer fossils helped you identify an extinction?

Dafna11 [192]

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3 years ago

Read 2 more answers

What is the temperature of 0.460 mol of gas at a pressure of 1.2 atm and a volume of 12.5 L ? Express your answer using two sign

Taya2010 [7]

The temperature is 370K.

The volume of a given fuel pattern is immediately proportional to its absolute temperature at regular pressure (Charles's law). The volume of a given amount of fuel is inversely proportional to its pressure whilst temperature is held steady (Boyle's regulation).

Density is immediately proportional to stress and indirectly proportional to temperature. As stress increases, with temperature constant, density will increase. Conversely when temperature increases, with strain regular, density decreases.

The equations describing those legal guidelines are unique cases of the best gasoline regulation, PV = NRT, wherein P is the pressure of the gas, V is its extent, n is the number of moles of the gas, T is its kelvin temperature, and R is the ideal (common) gas constant.

Learn more about pressure here: brainly.com/question/25736513

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2 years ago

Concentrated hydrogen peroxide solutions are explosively decomposed by traces of transition metal ions (such as Mn or Fe): 2H2O2

zalisa [80]

Answer:

23.0733 L

Explanation:

The mass of hydrogen peroxide present in 125 g of 50% of hydrogen peroxide solution:

$Mass=\frac {50}{100}\times 125\ g$

Mass = 62.5 g

Molar mass of $H_2O_2$ = 34 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles are:

$moles= \frac{62.5\ g}{34\ g/mol}$

$moles= 1.8382\ mol$

Consider the given reaction as:

$2H_2O_2_{(aq)}\rightarrow2H_2O_{(l)}+O_2_{(g)}$

2 moles of hydrogen peroxide decomposes to give 1 mole of oxygen gas.

Also,

1 mole of hydrogen peroxide decomposes to give 1/2 mole of oxygen gas.

So,

1.8382 moles of hydrogen peroxide decomposes to give $\frac {1}{2}\times 1.8382 mole of oxygen gas. Moles of oxygen gas produced = 0.9191 molGiven: Pressure = 746 torr
The conversion of P(torr) to P(atm) is shown below:
[tex]P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 746 / 760 atm = 0.9816 atm

Temperature = 27 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (27 + 273.15) K = 300.15 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9816 atm × V = 0.9191 mol × 0.0821 L.atm/K.mol × 300.15 K

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3 years ago