Answer:
The metal which reduces the other compound is the one higher in reactivity. So in this case, it is.
Explanation:
Answer:
E) rate of appearance of C = 0.45 M/s
rate of the reaction = 0.15 M/s
Explanation:
2A + B → 3C
Writing rate law for the reaction:
<u>Rate of reaction</u> = -
= -
= 
→ equation 1
Given that the rate of disappearance of A is 0.3 M/s
⇒ -
= 0.3 M/s
⇒Rate of reaction = - 
=
×0.3 M/s
⇒<u>Rate of reaction = 0.15 M/s</u>
From equation 1,
= - 
=
×0.3 M/s
⇒
= 0.45 M/s
or <u>the rate of appearance of C = 0.45 M/s</u>
The number of transferred electrons to form the ionic bond in one formula unit of each compound is as below
NaCl = 1 electron
CaS = 2 electrons
BaO= 2 electrons
KBr=1 electrons
LIF = 1 electron
explanation
ionic bond is formed between a metal and a nonmetal . This bond is formed when electron are transferred between cation and anion. To know how many electrons transferred you look the oxidation state of the metal.
for example
in NaCl only one electrons is transferred since Na is in oxidation state of +1. Na donate the one electron to Cl to form an ionic bond. Ba is in oxidation state of 2+ and hence it donate the two electrons to O to form ionic bond.
The answer is b) similar chemical properties but very different atomic numbers
Answer:

Explanation:
From the question we are told that:
pKa for Acetic Acid 
Therefore
For Equal Concentration of acetic acid and acetatic ion

Generally the Henderson's equation for pH value is mathematically given by



