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Alexxx [7]
2 years ago
15

How is locating -1.5 on a number line the same as locating 1.5 on a number line How is it different?​

Mathematics
1 answer:
Nezavi [6.7K]2 years ago
5 0
Locating -1.5 on a number line is the same as locating 1.5 because both numbers are the same distance from zero, but in opposite directions. The numbers also have the same absolute value.

Locating -1.5 and 1.5 is different because -1.5 can be found to the left of zero (because it is a negative number) while 1.5 is found to the right of zero (because it’s a positive number).
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Find the surface area no links no pdfs just type it into the answer section will give brainliest
rewona [7]

Check the picture below.

let's firstly convert the mixed fractions to improper fractions.

\stackrel{mixed}{7\frac{1}{2}}\implies \cfrac{7\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{15}{2}} ~\hfill \stackrel{mixed}{12\frac{1}{2}}\implies \cfrac{12\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{25}{2}} \\\\[-0.35em] ~\dotfill

\stackrel{\textit{\Large Areas}}{\stackrel{two~triangles}{2\left[ \cfrac{1}{2}\left(\cfrac{15}{2} \right)(10) \right]}~~ + ~~\stackrel{\textit{three rectangles}}{(10)(15)~~ + ~~\left( \cfrac{15}{2} \right)(15)~~ + ~~\left( \cfrac{25}{2} \right)(15)}} \\\\\\ 75~~ + ~~150~~ + ~~112.5~~ + ~~187.5\implies \boxed{525}

8 0
2 years ago
A point with coordinates (a, b) is plotted on a coordinated plane. The values of a and b can be any positive or negative integer
Diano4ka-milaya [45]

Answer:

Any negative and positive number can be your coordinates.

Step-by-step explanation:

As long as you don't have any restrictions as to what the coordinates can be, you're good to go!

Hope this helps!

8 0
3 years ago
Raiz cuadrada de 49?
beks73 [17]
Respuesta para tu pregunta jaja

5 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIEST
dusya [7]

1)

(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}

3)

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}

7 0
2 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS QUESTION what is -48-(-12)
olga_2 [115]

Answer:

-36

Step-by-step explanation:

-48+12=-36

6 0
3 years ago
Read 2 more answers
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