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Andrei [34K]
3 years ago
14

16) How many photons are contained in a burst of yellow light (589 nm) from a sodium lamp that contains 609 kJ of energy?

Chemistry
2 answers:
Len [333]3 years ago
4 0
The correct answer to this question is this one:

find the energy of one photon:

<span>E=h*<span>c/λ
</span></span>
divide the energy given by the energy of one photon of that wavelength

What I've done so far is convert wave length to m and energy to j. 

E photon = h * x / wave length
E = (6.626 x 10^-43)(3.00 x 10^8) / 587 ^ -9  = 3.38 x 10 ^18 J
3.38 x 10 ^18 J x 1000 kj / 1 j = 3.37 x 10 ^ 16 Kj
609 kJ/  3.37 x 10 ^ 16 Kj =  1.81 x 10 ^ 16

E = (6.626 x 10^-34)(3.00 x 10^8) / 587 ^ -9 = 3.38 x 10 ^19 J
3.38 x 10 ^19 J x 1000 kj / 1 j = 3.37 x 10 ^ -16 Kj
609 kJ/ 3.37 x 10 ^ 16 Kj = 1.81 x 10 ^ 18 but the answer is  1.81 × 10^24 photons

3.38 x 10 ^-19 J
should be negative

then 3.38 x 10 ^18 J x 1kJ/1000 J

you're converting from J to kJ.. just like meters to kilometres, you wouldn't multiply you would divide
kumpel [21]3 years ago
3 0

Answer:  C) 1.81\times 10^{24} photons

Explanation:

E=\frac{nhc}{\lambda}

E= energy = 609 kJ = 609000 J    (1kJ=1000J)

n = number of photons = ?

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of photon = 589 nm =589\times 10^{-9}m

Putting values in above equation, we get:

609000J=\frac{n\times (6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{589\times 10^{-9}m}

n=1.81\times 10^{24}

Thus there are 1.81\times 10^{24} photons in a burst of yellow light (589 nm) from a sodium lamp that contains 609 kJ of energy.

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<em>Kf </em>is the molal depression freezing constant.

<em>m</em> is the molality of the solute.

<em>The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. </em>

<em></em>

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<em>So, for sugar: i = 1.</em>

<em>∴ ΔTf for sugar = iKf.m = (1)(Kf)(2.0 m) = 2 Kf.</em>

<em></em>

  • For most ionic compounds dissolved in water, the van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

For NaCl, it is electrolyte compound which dissociates to Na⁺ and Cl⁻.

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The relation between heat and molar heat of fusion is,

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