Question

If a large marshmallow has a volume of 2.00 in3 and density of 0.242 g/cm3, how much would it weigh in grams? 1 in3=16.39 cm3.

Answer 1

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically,         Density = $\frac{mass}{volume}$

It is given that volume is 2 $in^{3}$ or 32.774 $cm^{3}$ (as 1 $in^{3}$ = 16.39 $cm^{3}$). Density is given as 0.242 $g/cm^{3}$.

Hence, calculate the mass of marshmallow as follows.

                     Density = $\frac{mass}{volume}$

             0.242 $g/cm^{3}$ = $\frac{mass}{32.774 cm^{3}}$

                       mass = 7.93 g

Thus, we can conclude that mass of given marshmallow is 7.93 g.

Answer 2

First convert the inches cubed to centimeters cubed. Looking at the rate, we can write 2 inches cubed = 2 * 16.39 cm cubed = 32.78 cm cubed.

The equation for density is D = M/V, where D is the density, M is the mass, and V is the volume. Substitute the values into the equation:

0.242 = M/32.78

Multiply by 32.78 on both sides.

The mass is about 7.93 grams.