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BaLLatris [955]
3 years ago
10

If a large marshmallow has a volume of 2.00 in3 and density of 0.242 g/cm3, how much would it weigh in grams? 1 in3=16.39 cm3.

Chemistry
2 answers:
scoundrel [369]3 years ago
5 0

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically,         Density = \frac{mass}{volume}

It is given that volume is 2 in^{3} or 32.774 cm^{3} (as 1 in^{3} = 16.39 cm^{3}). Density is given as 0.242 g/cm^{3}.

Hence, calculate the mass of marshmallow as follows.

                     Density = \frac{mass}{volume}

             0.242 g/cm^{3} = \frac{mass}{32.774 cm^{3}}

                       mass = 7.93 g

Thus, we can conclude that mass of given marshmallow is 7.93 g.

siniylev [52]3 years ago
3 0

First convert the inches cubed to centimeters cubed. Looking at the rate, we can write 2 inches cubed = 2 * 16.39 cm cubed = 32.78 cm cubed.

The equation for density is D = M/V, where D is the density, M is the mass, and V is the volume. Substitute the values into the equation:

0.242 = M/32.78

Multiply by 32.78 on both sides.

The mass is about 7.93 grams.

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