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4 years ago

a box half full of apples weighs 40kg and the same box one fifth full weighs 22kg, what does the box weigh when empty?

2 answers:

6 0

1/2 = 40kg
1/5 = 22kg
1/2 = 5/10
1/5 = 2/10
3/10 is the difference between 18kg.
This means 1/10 of the box filled with apples is 6kg.
<span>40 - (5 x 6) = 10kg. The box weighs 10kg alone. </span>

ruslelena [56]4 years ago

5 0

1/2 = 40kg
1/5 = 22kg
1/2 = 5/10
1/5 = 2/10
3/10 is the difference between 18kg.
This means 1/10 of the box filled with apples is 6kg.
40 - (5 x 6) = 10kg. The box weighs 10kg alone.

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3 years ago

Jose worked n hours at 8.75 dollars per hour he made a total of $61.25 write an expression that represents the total number of h

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Answer:

n = P/8.75

Step-by-step explanation:

Jose’s pay (P) depends on the number (n) of hours he works.

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n = P/8.75

=====

P = $61.25

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3 years ago

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4 years ago

Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?

Korvikt [17]

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Let's check how to determine the factors of our expression by grouping:

Step 1. Look for common multiples between the terms.

Notice that 4 and 8 are multiples of 2, 8 is a multiple of 4, and all of them are multiples of 1, so we are going to try more than one pairing combination.

Step 2. Look for common factors between the variables.

Usually, we want to pair variables with higher exponents so when we factor each pair, we end up with another common factor in binomial form.

Step 3. Factor each pair; if you end with another binomial common factor, you nailed it. If not, try again.

Les't apply our steps to our expression $4x^3+x^2-8x-2$

Applying step 1, we are pairing $4x^3$ and $-8x$ . Remember to pair the remaining factors as well.

$(4x^3-8x)+(x^2-2)$

The common factor in the first pair is $4x$ , so lets factor that out

$4x(x^2-2)+(x^2-2)$

Look! we have the binomial common factor $(x^2-2)$ . Unfortunately, $4x(x^2-2)+(x^2-2)$ is not in our given choices, so let's try again:

This time we are going to group the higher variables (step 2) $4x^3$ and $x^2$

$4x^3+x^2-8x-2$

$(4x^3+x^2)+(-8x-2)$

The common factor in the first pair is $x^2$ , and the common factor in the second one is -2, so let's factor out both of them:

$(4x^3+x^2)+(-8x-2)$

$x^2(4x+1)-2(4x+1)$

This time, we got option A.

We can conclude that the correct answer is: A) x2(4x + 1) – 2(4x + 1)

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4 years ago