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White raven [17]
3 years ago
5

Which calculation will determine power?

Mathematics
1 answer:
Setler [38]3 years ago
8 0

Answer & Explanation:

Mathematically, it is computed using the following equation. The standard metric unit of power is the Watt. As is implied by the equation for power, a unit of power is equivalent to a unit of work divided by a unit of time. Thus, a Watt is equivalent to a Joule/second

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Please answer with work explanation (if possible)
andrey2020 [161]

Answer:

$357.42

Step-by-step explanation:

So first I multiplied $425.50 by 20%.

$425.50 * 0.20=  85.10

$425.50- 85.10= $340.40

$340.40 * 0.05 = $17.02

$340.40 * 0.07 = $23.828

$340.40 + 23.828 + 17.02= $ 357.42

The sale price of Dean's guitar is $357.42.

4 0
3 years ago
Simplify the expression 3(6-2x)
ehidna [41]

Answer:

-3

Step-by-step explanation:

3 times 6 is 18

3 times -2x is -6x

put -6x on the other side and divide 18 by -6x and you get -3

4 0
3 years ago
Can someone help me with B? I’m really bad at this kind of stuff. I need help ASAP
Vinil7 [7]

Answer:

D = .44P

Step-by-step explanation:

We need to find the slope of the line

m = (y2-y1)/ (x2-x1)

Using two points

m = (22-4.4) /(50-10)

   = 17.6/40

   = .44 lb/ in^2 ft

We can use the point slope form of the equation

y-y1 = m(x-x1)  where y=D and x=P

D-4.4 = .44 (P-10)

Distribute

D-4.4 = .44P - 4.4

Add 4.4 to each side

D -4.4+4.4 = .44P -4.4+4.4

D = .44P

8 0
4 years ago
Read 2 more answers
Find the sum of the first 48 terms of the following series, to the nearest integer.
Usimov [2.4K]

Step-by-step explanation:

∑k=150(3k+2)

First find a1 and a50 :

a1=3(1)+2=5a20=3(50)+2=152

Then find the sum:

Sk=k(a1 + ak)2S50=50(5 + 152)2=3925

5 0
3 years ago
Read 2 more answers
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
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