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4 years ago

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One international nautical mile is defined as exactly 6076.1155ft ,and a speed of 1 knot is defined as one international nautica

l mile per hour. Question what is the speed in meter per second of a boat traveling at a speed of 18.8 knots

1 answer:

Anna [14]4 years ago

8 0

125,343,360 meters per second

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Why the mixture of bromine and ethane is discoloured when left in the sun

DENIUS [597]

Answer:

In the presence of UV light, ethane will react with bromine in a substitution reaction. UV light is the condition under which the reaction will occur so it is written above the arrow in the chemical equation. As the reaction proceeds, the intensity of the re-brown colour of the bromine water decreases.

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3 years ago

Read 2 more answers

The solid-state transition of Sn(gray) to Sn(white) is in equilibrium at 18.0 ˚C and 1.00 atm, with an entropy change of 8.8 J K

Vika [28.1K]

Answer:

Transition temperature = 13 C

Explanation:

ΔS(transition) = 8.8 J/K.mol

ρ(gray) = 5.75 g/cm³ = 5750 kg/m³

ρ(white) = 7.28 g/cm³ = 7280 kg/m³

ΔP = 100 atm = 100 x 101325 = 10132500 Pa

M(Sn) = 118.71g/mol = 118.71 x 10⁻³ kg/mol

T(i) = 18 C, T(f) = ?

We know that

G = H - TS, where G is the gibbs free energy, H is the enthalpy, T is the temperature and S is the entropy

H = V(m) x P, hence the equation becomes

G = V(m) x P - TS

The change in Gibbs free energy going from G(gray) to G(white) = 0 as no change of state takes place hence it can be said that

ΔG(gray) - ΔG(white) = 0

replacing the G with it formula shown above we can arrange the equation such as

0 = V(m)(gray) - V(m)(white) x ΔP - (ΔS(gray) - ΔS(white)) x ΔT

solving for ΔT we get

ΔT = {V(m)(gray) - V(m)(white) x ΔP}/(ΔS(gray) - ΔS(white))

ΔT = {M(Sn)(1/ρ(gray) - 1/ρ(white) x ΔP}/(ΔS(gray) - ΔS(white))

ΔT = {118.71 x 10⁻³ x {(1/5750) - (1/7280)} x 10132500}/(8.8)) = 5.0 C

ΔT = T(initial) - T(transition)

T(transition) = T(initial) - ΔT = 18 - 5 = 13 C

5 0

3 years ago

The _____________ is the temperature at which a substance changes from solid to liquid; ________________ is the temperature at w

Aleksandr-060686 [28]

The _____melting point________ is the temperature at which a substance changes from solid to liquid; _______boiling point_________ is the temperature at which a substance changes from a liquid to as gas; _______vapourisation_________ is the process by which atoms of molecules leave a liquid and become a gas.

5 0

4 years ago

Isotopes are separated by

Irina18 [472]

Answer:

1. C. distillation

2. B. conversion of mechanical energy into nuclear energy

3. B. Alpha ray

Explanation:

7 0

3 years ago

Tellurium has eight isotopes: Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), T

Elena-2011 [213]

The average atomic mass of tellurium, calculated from its eight isotopes (Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), Te-128 (31.79%), and Te-130 (34.48%)) is 127.723 amu.

The average atomic mass of Te can be calculated as follows:

$A = m_{Te-120}\%_{Te-120} + m_{Te-122}\%_{Te-122} + m_{Te-123}\%_{Te-123} + m_{Te-124}\%_{Te-124} + m_{Te-125}\%_{Te-125} + m_{Te-126}\%_{Te-126} + m_{Te-128}\%_{Te-128} + m_{Te-130}\%_{Te-130}$

Where:

m: is the mass

%: is the abundance percent

Knowing all the masses and abundance values, we have:

$A = 120*0.09\% + 122*2.46\% + 123*0.87\% + 124*4.61\% + 125*6.99\% + 126*18.71\% + 128*31.79\% + 130*34.48\%$

To find the <u>average atomic mass</u> we need to change all the <u>percent values</u> to <u>decimal ones</u>

$A = 120*9 \cdot 10^{-4} + 122*2.46 \cdot 10^{-2} + 123*8.7\cdot 10^{-3} + 124*4.61 \cdot 10^{-2} + 125*6.99\cdot 10^{-2} + 126*0.1871 + 128*0.3179 + 130*0.3448 = 127.723$

Therefore, the average atomic mass of tellurium is 127.723 amu.

You can find more about average atomic mass here brainly.com/question/11096711?referrer=searchResults

I hope it helps you!

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3 years ago