I think its B because if u increase the mass itll have more force which will increase the momentum
<span>Of all the sub-shells shown ( 1s ,2s ,2p ,3s ,3p ,4s ,3d ,4p ,5s ,4d ,5p ,6s ,4f ,5d) the ones that act as core orbital of HF (Hydrogen Fluoride) is 6s and 5d</span>
The question is incomplete, complete question is :
In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?
Structure is given in an image?
Answer:
There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
Explanation:
Total numbers of carbon = 10
Number of primary carbons that is carbon joined to just single carbon atom = 6
Number of secondary carbons that is carbon joined to two carbon atoms = 1
Number of tertiary carbons that is carbon joined to three carbon atoms = 2
Number of quartenary carbons that is carbon joined to four carbon atoms = 1
So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
Answer:
two hydrogen can bonded with oxygen to form H2O
Answer:
4.09ₓ10²³ atoms are contained in 10g of C₃H₈
Explanation:
1 mol of C₃H₈ has 3 mol of carbon and 8 mol of hydrogen.
1 mol of C₃H₈ weighs 44 g
In 44 g of C₃H₈ we have 3 mol of C
In 10 g of C₃H₈ we'll have (10 . 3)/ 44 = 0.681 mol
1 mol of C has NA (6.02x10²³) particles
0.681 mol will have (0.681 . 6.02x10²³) = 4.09ₓ10²³ atoms