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3 years ago

How do the weights of the tug of war teams affect the match

2 answers:

8 0

In Newton's Second Law of Motion, it simply states that mass x acceleration= force. So if there's more weight on one side and the same amount of acceleration on both side, then the side with more weight has more force. And with more force it tugs it more than the other side.

Shkiper50 [21]3 years ago

3 0

Because when the players lean towards their side, gravity pulls them backwards, it also makes it harder for the other side to pull someone so heavy. It's like a kid trying to pull their parent. Their parent is so much heavier that if the parent doesn't want to move they won't.

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The weight of an objects can be calculated by multiplying mass by

Lana71 [14]

Acceleration due to gravity.

7 0

3 years ago

Read 2 more answers

A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance trave

Svetradugi [14.3K]

Answer:

48m

Explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 6m/s

Time, t = 6 secs

Time, T2 = 5 secs

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation;

$a = \frac{6 - 0}{6}$

$a = \frac{6}{6}$

Acceleration, a = 1m/s²

To find the distance covered in the first phase;

Solving for distance, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Substituting the values into the equation;

$S = 0(6) + \frac {1}{2}*1*(6)^{2}$

$S = 0 + \frac {1}{2}*1*36$

$S = 0.5 *36$

Distance, S1 = 18m

For the second phase, time T2 = 5 secs;

Mathematically, speed is given by the equation;

$Speed = \frac{distance}{time}$

Making distance the subject of formula, we have;

$Distance, S = speed * time$

Substituting into the above equation;

$Distance, S = 6 * 5$

Distance, S2 = 30m

Total distance = S1 + S2 = 18m + 30m = 48m

Total distance = 48m

Therefore, the total distance traveled by the biker is 48m.

4 0

3 years ago

Which activity would be an appropriate first step

andriy [413]

Answer:

B. Researching the problem, using information from a variety of sources

Explanation:

First you must create a hypothesis because with out a hypothesis you can’t do the experiment. Then you have to do some research on your problem/ hypothesis from reliable sources. After have your research you can organize your data with a data table or chart. Then when have your research look for the independent and dependent variable and the control. Then you have to make a conclusion based on multiple experimental trials then repeat the experiment and if it ends up different from the first then something is wrong and that means that you did something wrong. Hopefully this helps you :)

pls mark brainlest ;)

3 0

3 years ago

How does human activity affect erosion and sedimentation

antoniya [11.8K]

Answer:

Human activity such as soil stripping, mining dangerous agricultural practice causes and affects erosion and sedimentation.

The earth operates a balanced process such that the earth produce it self at about the same rate as it erodes. So if humans are stripping the soil at a rate greater than the rate at which the soil is forming itself, the soil wont be able to keep up, thus leading to erosion.

Sedimentation on the other hand is the process whereby by particle settle at the base of the carrying body due to the force of gravity.

As humans, mining activity most importantly at times dissolves particles which travels down to the core and are then moved to another location by erosion. this implies that the strength of the soil of that location becomes weak.

7 0

3 years ago

A 14.0-g wad of sticky clay is hurled horizontally at a 90-g wooden block initially at rest on a horizontal surface. The clay st

vredina [299]

Answer:the speed of the clay immediately before impact =72.58m/s

Explanation:

Given that

mass of the stick clay, M₁= 14.0 g = 0.014 kg

mass of the block ,M₂= 90 g = 0.09 kg

Therefore the total mass= (M₁+M₂) = 104g = 0.104 kg

Also, distance, s = 7.50 m

coefficient of friction μ= 0.650

Acceleration due to gravity ,g = 9.8 m/s²

Using the Work- Energy theorem,

change in kinetic energy = work done

final kinetic energy(K₂) - initial kinetic energy(K₁) = force, F x coefficient of friction, μ x distance,s

The final kinetic energy is zero because after the impact, the block with the clay comes to a stop after 7.50m

kinetic energy =Work done

0.5 x m x v²=coefficient of friction, μ x force(F) x distance,s(Since force = m g )

0.5 x m x v²= μ x m x g x s

0.5 x 0.104 x v² = 0.650 x 0.104x 9.8 x 7.5

v²= 0.650 x 0.104x 9.8 x 7.5 / 0.5 x 0.104

v²==95.55

V = 9.77 m/s

Using the conservation of momentum formulae where

M₁ V₁ + M₂ V₂ = (M₁ + M₂ ) V

Since V₂ which is the velocity of block is zero as the block is initially at rest, We now have that

M₁ V₁ = (M₁ + M₂ ) V

0.014 kg x V₁ = 0.104 x 9.77

V₁=0.104 x 9.77 / 0.014

V=72.58m/s

5 0

2 years ago