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2 years ago

Pls help I will give brainlist and don’t give me a link I can’t open them

Physics

1 answer:

dezoksy [38]2 years ago

5 0

Answer:

200

Explain:

I have a big brain

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What is 64 nanometers to m?

defon

$\sf Hello!$

$\sf We\: know \:that,$
$\sf 1\: meter$ = $\sf 10^{9} nm$

$\sf Then,$

$\sf Distance\: in \:m$ = $\sf Distance\: in\: nm$ × $\dfrac{\sf 1}{\sf 10^{9}}\: \sf m$

⇒ $\sf Distance\: in \:m$ = $\sf 64 × 10^{-9} \:m$

⇒ $\sf Distance\: in\: m$ = $\sf 6.4 × 10^{-8} \:m$

~ $\sf iCarl$

3 0

3 years ago

Read 2 more answers

You’ve set up a frictionless car racetrack, with a loop of radius 0.5 m. Your toy car of mass 2 kg starts at rest at the top of

Anna007 [38]

Answer

h = 1.12 m

Explanation:

given,

mass of the car = 2 kg

radius = 0.5 m

let h be the height of the ramp

when the car reaches at the top point

gravity = centripetal force

$mg =\dfrac{mv^2}{r}$

$g =\dfrac{v^2}{r}$

$v = \sqrt{gr}$

using conservation of energy

$\PE_i = PE_f + KE_f$

$m g h = m g (2r)+\dfrac{1}{2}mv^2$

$g h =g (2r)+\dfrac{1}{2}(\sqrt{gr})^2$

$g h =2 gr +\dfrac{gr}{2}$

$h =\dfrac{5r}{2}$

$h =\dfrac{5\times 0.5}{2}$

h = 1.12 m

hence, height of the ramp should be greater than 1.12 m so that it can complete the loop.

4 0

3 years ago

What notecard word is defined: a substance or particles that a wave travel through.

puteri [66]

Answer:

medium

Explanation:

A substance or particle that wave travel through is called medium. There are two main types of such medium, some contains particles and some are vacuums.

Waves can travel through a vacuum which contains no particles.
Some can also contain particles.
Waves can interact in different ways with the medium.

7 0

2 years ago

What kind of change in light (shift) would you

Misha Larkins [42]

Red shift in the light coming towards us from other galaxies.

8 0

3 years ago

A child is sliding a toy block (with mass = m) down a ramp. The coefficient of static friction between the block and the ramp is

tiny-mole [99]

Answer:

$F=mg(sin(\theta )-0.25 cos(\theta ))$

Explanation:

The free body diagram of the block on the slide is shown in the below figure

Since the block is in equilibrium we apply equations of statics to compute the necessary unknown forces

N is the reaction force between the block and the slide

For equilibrium along x-axis we have

$\sum F_{x}=0\\\\mgsin(\theta )-\mu N-F=0\\\therefore F=mgsin(\theta)-\mu N......(\alpha )\\Similarly\\\sum F_{y}=0\\\\N-mgcos(\theta )=0\\\therefore N=mgcos(\theta ).......(\beta )\\\\$

Using value of N from equation β in α we get value of force as

$F=mg(sin(\theta )-\mu cos(\theta ))$

Applying values we get

$F=mg(sin(\theta )-0.25 cos(\theta ))$

8 0

3 years ago

Read 2 more answers