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2 years ago

Pls help I will give brainlist and don’t give me a link I can’t open them

Physics

1 answer:

dezoksy [38]2 years ago

5 0

Answer:

200

Explain:

I have a big brain

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Two identical satellites are in orbit about the earth. One orbit has a radius r and the other 2r. The centripetal force on the s

velikii [3]

Answer:

the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

Explanation:

Mass of satellite, m

orbit radius of first, r1 = r

orbit radius of second, r2 = 2r

Centripetal force is given by

$F= \frac{mv^{2}}{r}$

Where v be the orbital velocity, which is given by

$v=\sqrt{gr}$

So, the centripetal force is given by

$F= \frac{mgr}}{r}}=mg$

where, g bet the acceleration due to gravity

$g=\frac{GM}{r^{2}}$

So, the centripetal force

$F= \frac{GMm}}{r^{2}}}$

Gravitational force on the satellite having larger orbit

$F= \frac{GMm}{4r^{2}}$ .... (1)

Gravitational force on the satellite having smaller orbit

$F'= \frac{GMm}{r^{2}}$ .... (2)

Comparing (1) and (2),

F' = 4 F

So, the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

8 0

3 years ago

How can i tell the difference between a one element and another?

dybincka [34]

Normally, the number of electrons is equal to the number of protons, which makes atoms electrically neutral. The number of protons in an atom is the defining feature of an atom. It's what makes one element different from another

HOPE THIS HELPS!!!

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3 years ago

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Which sound wave-object interaction is used by animals in echolocation?

tekilochka [14]

The answer is reflection

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2 years ago

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True or false, russian twists focus to strengthen the latissimus dorsi

Oliga [24]

The answer is true hope that helped!!

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3 years ago

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roblem 10: In an adiabatic process oxygen gas in a container is compressed along a path that can be described by the following p

miskamm [114]

Answer:

W= -2.5 (p₁*0.0012) joules

Explanation:

Given that p₀= initial pressure, p₁=final pressure, Vi= initial volume=0 and Vf=final volume= 6/5 liters where p₁=p₀ then

In adiabatic compression, work done by mixture during compression is

W= $\int\limits^f_i {p} \, dV$ where f= final volume and i =initial volume, p=pressure

p can be written as p=K/V^γ where K=p₀Vi^γ =p₁Vf^γ

W= $\int\limits^f_i {K/V^} \, dV$

W= K/1-γ ( 1/Vf^γ-1 - 1/Vi^γ-1)

W=1/1-γ (p₁Vf-p₀Vi)

W= 1/1-1.40 (p₁*6/5 -p₀*0)

W= -2.5 (p₁*6/5*0.001) changing liters to m³

W= -2.5 (p₁*0.0012) joules

3 0

2 years ago