In what section of the EM spectrum can we find visible light?

22. Explain in detail what happens to particles before, during, and after vaporization.

Natasha2012 [34]

Answer:

Vaporization occurs when a substance changes from a liquid to a gas. The molecules in a liquid are in constant motion while staying relatively close together due to intermolecular forces. When an increase in temperature occurs, the molecules' kinetic energy also increases. If a liquid is heated the particles are given more energy and move faster and faster expanding the liquid. The most energetic particles at the surface escape from the surface of the liquid as a vapor as it gets warmer. Liquids evaporate faster as they heat up and more particles have enough energy to break away.

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3 0

4 years ago

Compare the gravitational acceleration on the following objects compared to the Sun using:

arsen [322]

The gravitational acceleration of White dwarf compared to Sun is 13,675.86.

The gravitational acceleration of Neutron star compared to Sun is 6.79 x 10⁻²⁴.

The gravitational acceleration of Star Betelgeuse compared to Sun is 8.5 x 10¹⁰.

<h3>Mass of the planets</h3>

Mass of sun = 2 x 10³⁰ kg

Mass of white dwarf = 2.765 x 10³⁰ kg

Mass of Neutron star = 5.5 x 10¹² kg

Mass of star Betelgeuse = 2.188 x 10³¹ kg

<h3>Radius of the planets</h3>

Radius of sun = 696,340 km

Radius of white dwarf = 7000 km

Radius of Neutron star = 11 km

Radius of star Betelgeuse = 617.1 x 10⁶ km

<h3>Gravitational acceleration of White dwarf compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.765 \times 10^{30}}{2\times 10^{30}} \times [\frac{696,340,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 13,675.86$

<h3>Gravitational acceleration of Neutron star compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{5.5 \times 10^{12}}{2\times 10^{30}} \times [\frac{11,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 6.79\times 10^{-24}$

<h3>Gravitational acceleration of Star Betelgeuse compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.188 \times 10^{31}}{2\times 10^{30}} \times [\frac{617.1 \times 10^9}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 8.5\times 10 ^{10}$

Learn more about acceleration due to gravity here: brainly.com/question/88039

3 0

3 years ago

A car advertisement claims their car can go from a stopped position to moving 60 miles per hour in 5 seconds. The advertisement

ASHA 777 [7]

The advertisement is deciribing the car’s acceleration, as it gains speed when moving from 0-60.

4 0

4 years ago

HELP ASAP PLS<br><br> Describe what characterizes science

r-ruslan [8.4K]

Science is characterized by empirical observations, testable questions, formation of hypotheses and experiments that result in stable and replicable results, logic reasoning and theoretical constructs

3 0

3 years ago

Ii.

notka56 [123]

Answer:

toaster -- 15 A, 8 Ω
fry pan -- 10.83 A, 11.08 Ω
lamp -- 0.83 A, 144 Ω
fuse will blow

Explanation:

P = VI

I = P/V = P/120

R = V/I = V/(P/V) = V^2/P = 14400/P

<u>Toaster</u>: I = 1800/120 = 15 . . . amps

R = 14400/1800 = 8 . . . ohms

<u>Fry pan</u>: I = 1300/120 = 10.833 . . . amps

R = 14400/1300 = 11.08 . . . ohms

<u>Lamp</u>: I = 100/120 = 0.833 . . . amps

R = 14400/100 = 144 . . . ohms

The total current exceeds 20 A, so will blow the fuse.

5 0

4 years ago