Answer:
Step-by-step explanation:
1) False: The function is decreasing (because the base, 1/3, is between 0 and 1).
2) True: The function is decreasing (see #1, above)
3) False: There is no x-intercept.
4) True: If x is 0, then y = (1/3)^0 = 1.
5) False: the range consists of the set of all real numbers greater than zero.
Answer:
Written in Python
def sums(n):
total = 0
for i in range(1,n+1):
if i%2 == 0:
total = total + i*2
else:
total = total + i
return(total)
Step-by-step explanation:
The function is written in Python
def sums(n):
This initializes total to 0
total = 0
This iterates through the integers that makes up n i.e. 1,2,3.....n
for i in range(1,n+1):
This checks if current digit is even
if i%2 == 0:
If yes, it adds the double of the digit
total = total + i*2
else:
If otherwise, it adds the digit
total = total + i
This prints the calculated sum or total
return(total)
To call the function from main, use the following:
print(sums(n))
Where n is a positive integer. i.e. 
y=4x+2. eq1
y=5x. eq2
4x=2-y
x=(2-y) /4
substitute in equation 2
y=5(2-y) /2
y=(10-5y)/2
4y=10-5y
9y=10
y=10/9
substitute in equation 2 or 1
substituting in equation 2
10/9=5x
x=10/45
x=10/45 y=10/9
you can verify it also.
HOPE IT HELPS!!
Change both 4 to 2^2 and 8 to 2^3
you now have 2^2(4x-5)=2^3(3x-4)
2(4x-5)=3(3x-4)
8x-10=9x-12
x=2