Answer:
A yard sale.
Step-by-step explanation:
lol
Answer:
Step-by-step explanation:
Problem One
All quadrilaterals have angles that add up to 360 degrees.
Tangents touch the circle in such a way that the radius and the tangent form a right angle at the point of contact.
Solution
x + 115 + 90 + 90 = 360
x + 295 = 360
x + 295 - 295 = 360 - 295
x = 65
Problem Two
From the previous problem, you know that where the 6 and 8 meet is a right angle.
Therefore you can use a^2 + b^2 = c^2
a = 6
b =8
c = ?
6^2 + 8^2 = c^2
c^2 = 36 + 64
c^2 = 100
sqrt(c^2) = sqrt(100)
c = 10
x = 10
Problem 3
No guarantees on this one. I'm not sure how the diagram is set up. I take the 4 to be the length from the bottom of the line marked 10 to the intersect point of the tangent with the circle.
That means that the measurement left is 10 - 4 = 6
x and 6 are both tangents from the upper point of the line marked 10.
Therefore x = 6
Answer:
Answer:
Step-by-step explanation:
Step-by-step explanation:
Answer:
The area is equal to 666km²
Step-by-step explanation:
Multiply 18 by 37 to get 666.
Answer:
a) m∠6 = 55 and m∠8= 55 - 20 --> m∠8= 35 x = 55
b) m∠7 = 40 and m∠9 = 140 x = 40
c) m∠8 = 46 and m∠7 = 46 x = 18
d) m∠6 = 63 and m∠7 = 27 x = 9
(just like the note says at the top each one is a different problem hence the different answer or each angle even if its the same one)
Step-by-step explanation:
I've attached my work
Sorry it took so long
Please give me feedback on my repsomse by commenting,
any way i can improve showing my work?
Hope it helps, let me know if you have questions !
Have a nice rest of your day :)
