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xenn [34]
3 years ago
12

how do you write the quotient (9+i) over (9-i) in standard form? I need the answer but more importantly, I need to learn how to

solve these kinds of problems.
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
6 0
Since they are the conjugates of each (9-a and 9+a are conjugates, or with any number replacing 9) , we multiply it by (9+i)/(9+i) to get (9+i)^2/(9-i^2)=(81+2i+i^2)/(9-(-1))=(81-1+2i)/(10)=80/10+2i/10=8+i/5. Conjugates work because they make i into i^2 (-1) without any of the sneaky i's in the middle!
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Okay so the first one is right.
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4 0
3 years ago
Read 2 more answers
Pls help w these thx <33
stepladder [879]

Answer:

36.81233927

13.02532494

Step-by-step explanation:

You need to use the law of sine for both of them

the law of sine is as follows:

\frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}

Question 1:

\frac{15}{\sin(64)}=\frac{10}{\sin(y)}\\y=36.81233927

Question 2:

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7 0
3 years ago
Mary has 12 video games. She purchases five new video games each month as part of a video game club.
Oxana [17]

Answer:

The answer to your question is:  V = 12 + 5n

Step-by-step explanation:

Data

Video games right now = 12

She purchases 5 video games each month

Equation = ?

# of video games in n month = V

Process

           - Consider the initial amount of video games

                                   V = 12

           - Now, consider the number of video games the buys each month and the months

                                 5n

           - Finally, join both terms

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3 years ago
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Liono4ka [1.6K]
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- x is positive when x negative.

So the domain for - √(-x) and √(-x) are the same: x less than or equal to zero.
4 0
3 years ago
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Gala2k [10]

Answer:

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7 0
3 years ago
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