Answer is: H₂PO₄⁻ (d<span>ihydrogen phosphate).
Chemical reaction: HPO</span>₄²⁻(aq) + H⁺(aq) ⇄ H₂PO₄⁻(aq).
According to Bronsted-Lowry
theory acid are donor of protons and bases are acceptors of protons (the
hydrogen cation or H⁺). Hydrogen phosphate is Bronsted base and it can accept proton and become conjugate acid.
Answer:
The answer to the question is C
Answer:
(3) 5.36
Explanation:
Since this is a titration of a weak acid before reaching equivalence point, we will have effectively a buffer solution. Then we can use the Henderson-Hasselbalch equation to answer this question.
The reaction is:
HAc + NaOH ⇒ NaAc + H₂O
V NaOH = 40 mL x 1 L/1000 mL = 0.040 L
mol NaOH reacted with HAc = 0.040 L x 0.05 mol/L = 0.002 mol
mol HAC originally present = 0.050 L x 0.05 mol/L = 0.0025 mol
mol HAc left after reaction = 0.0025 - 0.002 = 0.0005
Now that we have calculated the quantities of the weak acid and its conjugate base in the buffer, we just plug the values into the equation
pH = pKa + log ((Ac⁻)/(HAc))
(Notice we do not have to calculate the molarities of Ac⁻ and HAc because the volumes cancel in the quotient)
pH = -log (1.75 x 10⁻⁵) + log (0.002/0.0005) = 5.36
THe answer is 5.36
Answer:
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Explanation:
