Answer:
Products have a lower total Gibbs free energy in comparison with the reagents total Gibbs free energy.
Explanation:
Hello,
Exergonic chemical reactions are those that the overall Gibbs free energy is negative, it means that the products have a lower total Gibbs free energy, turning out into a spontaneous chemical reaction. Such reactions are thermodynamically possible under standard conditions and they usually release heat.
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Answer:
Do you have a picture?
Explanation:
Sometimes, pictures are required to answer questions.
Answer:
-1190.24 kJ
Explanation:
The enthalpy change in a chemical reaction that produces or consumes gases is given by the expression:
ΔH = ΔU + Δngas RT
where Δn gas is the change of moles of gas, R is the gas constant,and T is temperature.
Now from the given balanced chemical reaction, the change in number of mol gas is equal to:
Δn gas = mole gas products - mole gas reactants = 2 - 5/2 = -1/2 mol
Sionce we know ΔU and the temperature (298 K), we are in position to calculate the change in enthalpy.
ΔH = -1189 x 10³ J + (-0.5 mol ) 8.314 J/Kmol x 298 K
ΔH = -1.190 x 10⁶ J = -1.190 x 10⁶ J x 1 kJ/1000 J = -1.190 x 10³ J
Answer:
The correct answer is 0.09 percent.
Explanation:
Based on the given information, the atomic radius is 2 × 10⁻¹⁰ m. Now the atomic volume can be determined by using the formula, 4/3πr³. by putting the values we get,
v = 4/3πr³ = 4/3π(2×10⁻¹⁰ m)³
v = 3.35 × 10⁻²⁹ m³
The no. of atoms present in one mole of xenon is 6.02 × 10²³ atoms. Therefore, the total atomic volume will be,
Va = 6.02 × 10²³ × 3.35 × 10⁻²⁹
Va = 2.02 × 10⁻⁵ m³
The %age of total volume occupied can be determined by dividing the total atomic volume with the volume under STP. Under STP, the volume is 22.4 m³ or 2.24 × 10⁻² m³.
Va/V = 2.02 × 10⁻⁵ m³ / 2.24 × 10⁻² m³
= 9.02 × 10⁻⁴ or 0.09 %
Answer:
Pressure = 47.1kPa
Explanation:
V1 = 5.0L
P1 = 94.2kPa = 94.2*10³Pa
V2 = 2V1 = 2 * 5.0 = 10L
P2 = ?
To solve this question, we'll have to use Boyle's law which states that the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant
Mathematically,
V = k/P, k = PV
P1V1 = P2V2 = P3V3=........=PnVn
P1V1 = P2V2
Solve for P2
P2 = (P1 * V1) / V2
P2 = (94.2*10³ * 5.0) / 10
P2 = 47100Pa
P2 = 47.1kPa
The new pressure of the gas is 47.1kPa
