Answer is: density of methane is 1.176 g/L.<span>
V(CH</span>₄<span>) =
1 L.
T = 75°C = 348.15 K.
p = 2.1 atm.
R = 0.08206 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.
n<span> = p·V / R·T.
n</span></span>(CH₄) = 2.1 atm · 1 L / 0.08206 L·atm/mol·K · 348.15 K.
n(CH₄) = 0.0735 mol.
m(CH₄) = n(CH₄) · M(CH₄).
m(CH₄) = 0.0735 mol · 16 g/mol.
m(CH₄) = 1.176 g.
d(CH₄) = m(CH₄) ÷ V(CH₄).
d(CH₄) = 1.176 g/L.
Answer:
The compound that will accumulate is B.
Explanation:
Enzymes in any biochemical process are the protein molecules that speed up the rate of the biological reaction. It lowers down the activation energy of the reactant molecules.
Since from the question:
<u>A + E1 –> B + E2 –> C</u>
Given that A, B and C are the molecules in the pathway and E1 and E2 are the enzymes.
<u>This means that A undergoes some biological reaction in which E1 is acting a catalyst to give B and which further undergoing another biological reaction to give C in the presence of enzyme E2.</u>
Since, E2 is inactive,
<u>A will form B but B will not be able to undergo further reaction and thus, C can not be formed.</u>
<u>Thus A is consumed and C is not formed. The compound that will accumulate is B.</u>
By giving the dog 2 or more different dog foods and seeing what one he eats the must of and the variables u control is how much you give the dog and the hypothesis is if I give the dog two or more different kinds of dog food than we will see what one he/she like the most
Answer:
Explanation:
Fe⁺²(aq) + ClO₂(aq) → Fe⁺³(aq) + ClO₂⁻(aq)
Here oxidation number of Fe is increased from +2 to +3 , so Fe is oxidised .
The oxidation number of Cl is reduced from + 4 to +3 so Cl is reduced .
So ClO₂(aq) is oxidising agent and Fe⁺²(aq) is reducing agent .
