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gladu [14]
3 years ago
12

Energy is just like any other chemical or physical process, where it cannot be created or destroyed. Which Law states this fact?

Chemistry
1 answer:
Ganezh [65]3 years ago
5 0

Answer:

Law of Conservation of Energy

Explanation:

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The unbalanced equation for the reduction of copper(I) sulfide with oxygen is given below. What mass of copper is produced from
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<u>Answer:</u> The mass of copper produced is 7.12 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of copper (I) sulfide = 8.80 g

Molar mass of copper (I) sulfide = 156.2 g/mol

Putting values in equation 1, we get:

\text{Moles of copper (I) sulfide}=\frac{8.80g}{156.2g/mol}=0.056mol

The chemical equation for the reaction of copper (I) sulfide and oxygen gas follows:

Cu_2S+O_2\rightarrow 2Cu+SO_2

By Stoichiometry of the reaction:

1 mole of copper (I) sulfide produces 2 moles of copper

So, 0.056 moles of copper (I) sulfide will produce = \frac{2}{1}\times 0.056=0.112mol of copper

Now, calculating the mass of copper from equation 1, we get:

Molar mass of copper = 63.55 g/mol

Moles of copper = 0.112 moles

Putting values in equation 1, we get:

0.112mol=\frac{\text{Mass of copper}{63.55g/mol}\\\\\text{Mass of copper}=(0.112mol\times 63.55g/mol)=7.12g

Hence, the mass of copper produced is 7.12 grams

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Neve later believes that New Zealand's winter is caused by the sun circling to the other side
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What grade percentage is developing, proficient, exceeding, and emerging?​
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If i have 340mL of a 1.5 M NaBr solution, What will the concentration be for 1000mL?
Gekata [30.6K]

Answer:

0.51M

Explanation:

Given parameters:

Initial volume of NaBr = 340mL

Initial molarity  = 1.5M

Final volume  = 1000mL

Unknown:

Final molarity = ?

Solution;

This is a dilution problem whereas the concentration of a compound changes from one to another.

In this kind of problem, we must establish that the number of moles still remains the same.

    number of moles initially before diluting = number of moles after dilution

Number of moles  = Molarity x volume

Let us find the number of moles;

          Number of moles  = initial volume x initial molarity

Convert mL to dm³;

                  1000mL  = 1dm³

                     340mL gives \frac{340}{1000}   = 0.34dm³

Number of moles  = initial volume x initial molarity  = 0.34 x 1.5 = 0.51moles

Now to find the new molarity/concentration;

               Final molarity  = \frac{number of moles}{Volume}    = \frac{0.51}{1}    = 0.51M

We can see a massive drop in molarity this is due to dilution of the initial concentration.

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