Sorry it’s messy, hope this helps :]
Answer:
0.00500M of Na₂C₂O₄
Explanation:
<em>When are dissolved in 150 mL of 1.0 M H2SO4.</em>
<em />
We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:
0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄
In 0.150L:
7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =
<h3>0.00500M of Na₂C₂O₄</h3>
Number of moles = mass/ molar mass
= 45.6g / 88.90g/mol
= 0.512 moles
Answer:
im confused on what you mean
Explanation:
Answer:
the mass of the glycerine needed in the given solution is 23.92 g
Explanation:
Given;
molarity of the solution (C₃H₈O₃), C = 2.60 M
Volume of the solution, V = 100 mL = 100 x 10⁻³ L = 0.1 M
The molarity of a solution is given as follows;

The molecular mass of the given solution;
molecular mass = (12 x 3) + (8 x 1) + (16 x 3)
molecular mass = 92 g/mol
The mass of the glycerine needed in the given solution is calculated as follows;
reacting mass = amount of solute (moles) x molecular mass (g/mol)
reacting mass = 0.26 x 92
reacting mass = 23.92 g
Therefore, the mass of the glycerine needed in the given solution is 23.92 g