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gladu [14]
4 years ago
12

Energy is just like any other chemical or physical process, where it cannot be created or destroyed. Which Law states this fact?

Chemistry
1 answer:
Ganezh [65]4 years ago
5 0

Answer:

Law of Conservation of Energy

Explanation:

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Sorry it’s messy, hope this helps :]

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Calculate the concentration of the resulting sodium oxalate solution if 0.1005 g of Na2C2O4 was used.
sashaice [31]

Answer:

0.00500M of Na₂C₂O₄

Explanation:

<em>When are dissolved in 150 mL of 1.0 M H2SO4.</em>

<em />

We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:

0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄

In 0.150L:

7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =

<h3>0.00500M of Na₂C₂O₄</h3>
4 0
3 years ago
How many moles are there in 45.6 grams of yttrium?
leva [86]
Number of moles = mass/ molar mass
= 45.6g / 88.90g/mol
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4 0
3 years ago
Apply Why does a box on the seat of a car
olga2289 [7]

Answer:

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Explanation:

3 0
3 years ago
How many grams of glycerine, C3H8O3, are needed to make 100. mL of 2.60 M solution?
Masteriza [31]

Answer:

the mass of the glycerine needed in the given solution is  23.92 g

Explanation:

Given;

molarity of the solution (C₃H₈O₃), C = 2.60 M

Volume of the solution, V = 100 mL = 100 x 10⁻³ L = 0.1 M

The molarity of a solution is given as follows;

Molarity = \frac{amount \ of \ solute \ (moles)}{volume \ of \ solution \ (L)} \\\\amount \ of \ solute \ (moles) = Molarity  \ \times volume \ of \ solution \ (L)\\\\amount \ of \ solute \ (moles) = 2.6 \times 0.1 \\\\amount \ of \ solute \ (moles) = 0.26 \ mole

The molecular mass of the given solution;

molecular mass = (12 x 3) + (8 x 1) + (16 x 3)

molecular mass = 92 g/mol

The mass of the glycerine needed in the given solution is calculated as follows;

reacting mass = amount of solute (moles)   x   molecular mass (g/mol)

reacting mass = 0.26 x 92

reacting mass = 23.92 g

Therefore, the mass of the glycerine needed in the given solution is  23.92 g

7 0
3 years ago
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