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Oduvanchick [21]
3 years ago
6

The following chemical reaction takes place in aqueous solution: 2FeBr3 (aq) + 3Na2S (aq) → Fe2S3 (s) + 6NaBr (aq) Write the net

ionic equation for this reaction.
Chemistry
1 answer:
lakkis [162]3 years ago
5 0
A net ionic equation simply means to cancel out any ions which appear on both sides of the chemical equation that are not involved in the reaction - they're called spectator ions. 
We'll first write out the full ionic equation, showing all ions and compounds formed, then rewrite and not include spectator ions.

2FeBr3(aq) + 3Na2S(Aq) --> Fe2S3(s) + 6NaBr(aq)   [original eqation]

2Fe3+(aq) + 6Br-(aq) + 3Na+(aq) + 3S2-(aq)--> Fe2S3(s)+6Na+(aq) + 6Br-(aq)
[full ionic equation]

2Fe3+(aq) + 3S2-(aq)--> Fe2S3(s)   [net ionic equation]

notice that Br- and Na+ appear unreacted on both sides of the full ionic equation, so they cancel out and do not appear in the net ionic.

*Please give me a 'brainliest' if you can! Thanks!


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3 0
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A compound consisting of B, N, and H undergoes elemental analysis. The % composition by mass is found to be 40.28% B, 52.20% N,
swat32

Empirical formula is the simplest ratio of components making up a compound.

The percentage composition of each element has been given

therefore the mass present of each element in 100 g of compound is

                      B                                   N                         H

mass          40.28 g                         52.20 g                 7.53 g

number of moles  

                 40.28 g / 11 g/mol      52.20 g / 14 g/mol    7.53 g / 1 g/mol

                = 3.662 mol                  = 3.729 mol             = 7.53 mol

divide the number of moles by the least number of moles, that is 3.662

                3.662 / 3.662              3.729 / 3.662              7.53 / 3.662

               = 1.000                           = 1.018                        = 2.056

the ratio of the elements after rounding off to the nearest whole number is

B : N : H = 1 : 1 : 2

therefore empirical formula for the compound is B₁N₁H₂          

that can be written as BNH₂    

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