Alkali metals.
Elements found in group 1 of the periodic table.
The suggested answers are for K=298 degrees and the nearest correct answer seems to be increase the room temperature by 22 degrees Fahrenheit. But by calculation, for 300 K, then convert 300k to degrees Celsius = 300-273.15=26.85 degrees celsius. Then convert the 26.85 to degrees F, so F=9/5C + 32= 48.33+32=80.33-55F (present room temperature)=25.33 degrees F to increase the room temperature by.
<u>Answer:</u> The wavelength of the flame is 462 nm and color of cesium flame is blue.
<u>Explanation:</u>
To calculate the wavelength, we use Planck's equation, which is:

where,
E = Energy of 1 photon = 
h = Planck's constant = 
c = speed of light = 
= wavelength = ?
Putting values in above equation, we get:

The range of wavelength of blue light lies in range of 500 nm - 435 nm
The calculated wavelength lies in the above range. So, the color of the cesium flame is 462 nm
Hence, the wavelength of the flame is 462 nm and color of cesium flame is blue.
It has bent geometry, which is similar to H2O, with the same angle of 109.5 degrees between 2 single H-S bonds.