Why haven’t I ever came across this question lol.
Answer:
0.129 L = 129.0 mL.
Explanation:
- NaOH neutralizes acetic acid (CH₃COOH) according to the balanced reaction:
<em>NaOH + CH₃COOH → CH₃COONa + H₂O. </em>
- According to the balanced equation: 1.0 mole of NaOH will neutralize 1.0 mole of CH₃COOH.
<em>no. of moles of CH₃COOH = mass/molar mass </em>= (2.0 g)/(60 g/mol) = <em>0.033 mole. </em>
<em>
</em>
no. of moles = (0.258 mol/L)(V)
- At neutralization: no. of moles of NaOH = no. of moles of CH₃COOH
∴ (0.258 mol/L)(V) = 0.033 mole
<em>∴ The volume of NaOH</em> = (0.033 mole)/(0.258 mol/L) = <em>0.129 L = 129.0 mL.</em>
Answer:
BE DIRECT, DON'T BE AFRAID. THE FACT THAT THEY ARE OF THE SAME SEX IS NOT RELEVANT.
SPEAK FROM THE HEART, EXPRESS YOUR FEELINGS HONESTLY.... AND IF HE REJECTS YOU, SMILE AND THINK "AT LEAST I TRIED, SOMEONE BETTER WILL EXIST" AND DON'T LET YOURSELF BE PUT DOWN UWU
Explanation:
(SORRY IF IT'S NOT VERY UNDERSTANDABLE, I SPEAK SPANISH AND I'M USING TRANSLATOR ._.)
Answer:
Option NH 3 is the correct answer.
Explanation:
A molecule which has hydrogen bonding will have the highest boiling point. So, out of the given options only NH 3 will have hydrogen bonding.
Whereas in CHCI 3 there will be dipole-dipole interactions and no hydrogen bonding within the molecule.
In OF 2 and C 6H 6, there will be dipole-dipole interaction in both the molecules.
Thus, we can conclude that NH 3 will have the highest boiling point.
Answer:
The most stable conformation of the following compound has
A. An axial methyl group and an axial ethyl group.
B. An axial methyl group and an equatorial ethyl group.
C. An axial tert-butyl group.
D. An equatorial methyl group and an equatorial ethyl group.
E. An equatorial methyl group and an axial ethyl group.
Explanation:
The most stable conformation in the cyclohexane ring is the one in which both the substituents are in the equatorial position.
Among the given options,
option D An equatorial methyl group and an equatorial ethyl group.
When the substituents in the cyclohexane ring are in equatorial positions then, the steric repulsions will be reduced.
Answer is option D.
