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Oksi-84 [34.3K]
3 years ago
7

Crystals of sodium chloride were prepared by the following method.

Chemistry
1 answer:
Kryger [21]3 years ago
8 0

Answer: the answer is C

IF U MIGHT NEED AN EXPLANATION FEEL FREE TO COMMENT

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One of the few xenon compounds that form is cesium xenon heptafluoride (CsXeF7). How many moles of CsXeF7 can be produced from t
larisa [96]
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6 0
3 years ago
Read 2 more answers
At a certain temperature, Kc = 0.0500 and ∆H = +39.0 kJ for the reaction below, 2 MgCl2(s) + O2(g) → 2MgO(s) + Cl2(g) Calculate
Minchanka [31]

Explanation:

Since, it is shown that the reaction has been reversed. Therefore, value of K_{c} will become \frac{1}{K_{c}}.

Hence, new K_{c'} = \frac{1}{K_{c}}

                                      = \frac{1}{0.0500}

                                      = 20

Also, the number of moles of each reactant has been halved. So, K_{c''} for the reaction MgO(s) + \frac{1}{2}Cl2(g) → MgCl_{2}(s) + \frac{1}{2} O2(g) will also get halved.

Therefore,     K_{c''}  = K_{c'} = (20)^{0.5}

                               = 4.47

As the value of \Delta H is given as +39.0 kJ. So, it means that the reaction is endothermic in nature. So, energy of reactants will be more than the products. Hence, according to Le Chatelier's principle reaction will move in the forward direction.

As a result, K_{c} will also increase with increase in temperature.

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4 years ago
Why does it seem to us as if rocks remain the same and don't change
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