Answer:
The IHD = 0
There is no unsaturation in the compound C4H9Cl
Explanation:
IHD = Index for Hydrogen Deficiency .It determines total number of unsaturation or Pi- bond present in the molecule.It is calculated using the formula:
For Molecule:
Here . C = carbon
H = Hydrogen
O = Oxygen
N = Nitrogen
X = Halogen
The IHD is calculated as :
...............(1)
For example :
C4H8O2
Here c = 4 , h = 8 , o = 2 .
n = x=0
Put the value in equation (1) and find IHD
IHD = 1
For C4H9Cl
c = 4 , h = 9 and x = 1
IHD for this molecule can be calculated as :
= 0
This means there is no unsaturation in the molecule.
Each bond is sigma bond and properly saturated.
I believe it is the dependent variable b/c it is the thing(s) that is been observe or measure
Answer:
The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams
Explanation:
The question is with regards to density calculations
The density of the given sodium carbonate solution, ρ = 0.4 g/dm³
The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³
Therefore, we have;
The mass, "m", of the sodium carbonate in = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g
The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.
Answer: The density of Ammonia is 0.648 g/l
Explanation:
Density = Mass/ Volume
Mass of one mole of Ammonia (NH3) = 17.031g
Volume =?
Using the ideal gas law we can determine the volume.
PV = nRT
P = 0.913 atm, V= ?, n = 1, R = 0.08206 L.atm/K, and T= 293K
Make V the subject of the formular, we then have;
V= nRT/ P = 1 mol x 0.08206 L.atm/ K.mol x 293 / 0.913 atm
V = 24.04358/ 0.913 = 26.3L
Having gotten the value of Volume in this question, we then go back to solve for density.
Density = Mass/ Volume
17.031g/ 26.3L = 0.64756 ≈ 0.648 g/l
Answer:
your answer may be found on a website called "Thought.co"
once you get there just search "Examples of Chemical Reactions in Everyday Life" and it will give you some ideas :)
