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Anna11 [10]
3 years ago
7

Which term describes a consumer that eats both plants and animals? A. carnivore B. herbivore C. omnivore D. producer

Chemistry
2 answers:
Roman55 [17]3 years ago
8 0

c. omnivore because im pretty sure it not carnivore XD

andreev551 [17]3 years ago
5 0

C. Omnivore (like humans)  Carnivores eat only meat Herbivores eat only plants

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Which will NOT occur when a light tray ray interacts with a smooth pane of glass?
zhuklara [117]

Answer:

B) diffraction

Explanation:

A smooth pane of glass does not diffract light. A light passing through a smooth pane of glass may be absorbed, reflected or transmitted.

Diffraction only occurs with special types of glasses embedded with a diffraction grating and are called super prisms. Diffraction glasses use a a gradient lens which is able to  separate light into all the colors of the rainbow.

Recall that diffraction is the separation of white light into its component wavelengths.

5 0
3 years ago
This chemical equation represents the burning of methane, but the equation is incomplete. What is the missing coefficient in bot
Zolol [24]
CH4+(x)O2=CO2 +(Y)H2O
C=1 +H=4 +O=? = C=1 +O=2+? +H=?
H=4>>Y=2
C=1 +H=4 +O=? = C=1 +O=(2+2) +H=4
C=1 +H=4 +O=4 = C=1 +O=4 +H=4
O=4>>X=2
CH4+(2)O2 =CO2 +(2)H2O

6 0
3 years ago
Read 2 more answers
In an experiment, a 0.5297 g sample of diphenylacetylene (C14H10) is burned completely in a bomb calorimeter. The calorimeter is
V125BC [204]

Answer:

the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

Explanation:

Given that:

mass of diphenylacetylene (C_{14}H_{10}) = 0.5297 g

Molar Mass of diphenylacetylene (C_{14}H_{10}) = 178.21 g/mol

Then number of moles of diphenylacetylene (C_{14}H_{10})  = \frac{mass}{molar \ mass}

= \frac{0.5297  \ g }{178.24 \  g/mol}

= 0.002972 mol

By applying the law of calorimeter;

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = Heat absorbed by H_2O + Heat absorbed  by the calorimeter

Heat liberated  by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  =  msΔT + cΔT

= 1369 g  × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C

= 17756.48 J + 2842.39 J

= 20598.87 J

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = 20598.87 J

Heat liberated by 1 mole of  diphenylacetylene (C_{14}H_{10}) will be = \frac{20598.87 \ J}{0.002972 \ mol}

= 6930979.139 J/mol

= 6930.98 kJ/mol

Since heat is liberated ; Then, the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

3 0
3 years ago
Read 2 more answers
Indicate whether each of the following would increase or decrease the rate of reaction
mote1985 [20]

The rate of a chemical reaction is affected by temperature, Catalysts, Suface area, Concentration.

<h3>Rate of reaction</h3>

The rate of a chemical reaction is the rate at which the concentration of reactant molecules decreases or the concentration of product molecules increases.

<h3>Factors effecting rate of chemical reaction </h3>

The factors that affect the rate of chemical reaction include:

  1. Temperature: increase in temperature increases reaction rate while decrease in temperature decreases reaction rate.
  2. Catalysts: the present of catalysts increase the reaction rate. Some catalysts decreases reaction rate and are known as negative catalysts.
  3. Surface area: increase in surface area of reactants increases reaction rate.
  4. Concentration: Increase in concentration of reactants increases reaction rate while decrease in concentration of reactants decreases reaction rate.

Therefore, the rate of a chemical reaction is affected by temperature, Catalysts, Suface area, Concentration.

Learn more about rate of reaction and factors affecting reaction rate at: brainly.com/question/15841605

7 0
2 years ago
Please help me!!!!!!!!!!!!!
fenix001 [56]

1)The limiting reactant will be aluminum acetate

2) The mass of aluminum hydroxide formed will be 9.75 grams.

<h3>Stoichiometric problem</h3>

The equation of the reaction is as below:

Al(C_2H_3O_2)_3 + 3NaOH --- > 3C_2H_3NaO_2 + Al(OH)_3

The mole ratio of the 2 reactants is 1:3.

Mole of 100 mL. 1.25 mol/L Al(C_2H_3O_2)_3 = 0.1 x 1.25 = 0.125 mol

Mole of 300 mL, 2.30 mol/L NaOH = 0.3 x 2.3 = 0.69 mol

Thus, aluminum acetate is limited.

Mole ratio of  Al(C_2H_3O_2)_3 and Al(OH)_3 = 1:1

Equivalent mole of Al(OH)_3 = 0.125 mol

Mass of 0.125 mole Al(OH)_3 = 0.125 x 78 = 9.75 grams.

More on stoichiometric calculations can be found here: brainly.com/question/27287858

#SPJ1

4 0
2 years ago
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