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anzhelika [568]
3 years ago
5

How many moles are in 4.3 x 10 ^22 molecules of Na3PO4

Chemistry
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

0.071 moles of Na₃PO₄ .

Explanation:

Given data:

Number of molecules of Na₃PO₄ = 4.3× 10²² molecules

Number of moles = ?

Solution:

1 mole contain 6.022 × 10²³ molecules

4.3× 10²² molecules × 1 mol / 6.022 × 10²³ molecules

0.71× 10⁻¹ mol

0.071 mol

The number 6.022 × 10²³ is called Avogadro number.

"It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance"

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For each of the salts below, match the salts that can be compared directly, using Ksp values, to estimate solubilities.
Anni [7]

Answer:

1 - Salts required  that can be compared directly, using Ksp values, to estimate solubilities for copper (II) sulfide are - CaSO_3 (Option b) ,BaCrO_4 (Option c) and CaS (Option d)

2 - Salts  that can be compared directly, using Ksp values, to estimate solubilities for zinc hydroxide are - Mg(OH)_2 (Option a)

Explanation:

K_s_p values can be used to compare the solubility of salts that produce ions in a 1:1 ratio.

  1. CuS {copper (II)sulfide} dissociates with ions in ratio 1:1 .

Because the salts CaSO_3 , BaCrO_4 and CaS  have a 1:1 ion ratio, the solubilities of options b, c, and d can be compared to salt 1.

K_s_p Values can be used to compare the solubility of salts that produce ions in a 1:2 or 2:1 ratio.

  2. Zn(OH)_2 dissociates into ions in ratio 1:2 .

Because the ions in the salt Mg(OH)_2 are in a 1:2 ratio, the solubility of salt 2 can be compared to that of salt 'a'.

Hence , Salt 1 is matched with options b , c , d.

              Salt 2 is matched with option a.

4 0
3 years ago
Marvin records scientific data about Lake Superior. For which property has Marvin forgotten to use an SI unit of measurement?
Illusion [34]

Answer: low temperature

Explanation:-

S.I or M.K.S is a system for defining physical units as meter, kilogram, second, ampere, kelvin or celcius, candela, and mole together with a set of prefixes to indicate multiplication or division by a power of ten for measuring length, mass, time , current, temperature and amount of substance respectively.

Given :

lake length = 563 kilometers = 563\times 10^3m

High temperature =76.5^0F

Low temperature =-6.3^0C

annual precipitation =762 mm= 762\times 10^{-3}m

Thus low temperature in units of Fahrenheit is not an S.I unit of measurement.

8 0
3 years ago
Read 2 more answers
Carbonates are typically insoluble, but one exception would be a carbonate containing what kind of cation? a) ammonium b) a tran
KATRIN_1 [288]

For a carbonate containing a kind of cation, we have that Option 1 is the correct answer: ammonium.

<h3>What are Carbonates?</h3>

Generally, Any of two families of chemical substances generated from carbonic acid or carbon dioxide is referred to as carbonate.

In conclusion, Sodium, potassium, and ammonium are the three carbonates that are soluble.

Read more about Compound

brainly.com/question/704297

4 0
2 years ago
How many gallons of gasoline that is 5% ethanol must be added to 2,000 gallons of gasoline with no ethanol to get a mixture that
Amanda [17]

Answer:

V_1= 3000 gal

Explanation:

We have 3 solutions:

  • Solution 1 (with ethanol)
  • Solution 2 (no ethanol)
  • Final solution

V_f=V_1 + V_2

and for the ethanol:

V_f*0.03=V_1*0.05 + V_2*0

V_f=V_1 \frac{5}{3}

Combining:

V_1 \frac{5}{3}=V_1 + V_2

V_1 \frac{2}{3}= V_2

V_1= \frac{3}{2} V_2

If V2=2000 gal:

V_1= \frac{3}{2} 2000 gal

V_1= 3000 gal

8 0
3 years ago
A certain metal M forms a soluble sulfate salt MSO, Suppose the left half cell of a galvanic cell apparatus is filled with a 3.0
dimaraw [331]

Explanation:

It is known that for high concentration of M^{2+}, reduction will take place. As, cathode has a positive charge and it will be placed on left hand side.

Now, E^{o}_{cell} = 0 and the general reaction equation is as follows.

         M^{2+} + M \rightarrow M + M^{2+}

                3.00 M        n = 2       30 mM

         E = 0 - \frac{0.0591}{2} log \frac{50 \times 10^{-3}}{1}

            = -\frac{0.0591}{2} log (5 \times 10^{-2})

            = 0.038 V

Therefore, we can conclude that voltage shown by the voltmeter is 0.038 V.

5 0
3 years ago
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