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Galina-37 [17]
3 years ago
6

Which of the following would have the highest viscosity?

Chemistry
2 answers:
romanna [79]3 years ago
7 0
Honey is the correct answer.  
melisa1 [442]3 years ago
4 0
Honey, viscosity is a measurement of resistance to flow.
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Help me asappp please
Basile [38]

Answer:

wait

Explanation:

wait

3 0
3 years ago
What is the connection between physical properties and physical changes
irakobra [83]

Answer: Physical changes are related to physical properties since some measurements require that changes be made. Melting Point: As solid matter is heated it eventually melts or changes into a liquid state at the melting point. Ice (a solid form of water) melts at 0 oC and changes to the liquid state.

Explanation:

5 0
2 years ago
Read 2 more answers
What do methanol (CH2O), ethanoic acid (C2H4O2), and glucose (C3H6O3) all have in common?
tatyana61 [14]

Answer:

d

Explanation:

Carbohydrates are compounds containing carbon, hydrogen, and oxygen. Therefore, a is true.

An empirical formula is the simplest ratio of atoms present in a compound. Therefore, C2H4O2 and C3H6O3, (if you simplified them like you would a fraction) would be CH2O. Therefore b is correct,

They also have the same % composition, with a ratio of 1 carbon : 2 hydrogen : 1 oxygen. Therefore, c is correct.

Since a, b and c are all correct, the answer is d, all of the above are true.

6 0
4 years ago
HELPPPPPP PLEASEEEEEE
attashe74 [19]
D I believe. Correct me if I’m wrong.
4 0
3 years ago
Read 2 more answers
How much energy is required to raise the temperature of 10.7 grams of gaseous helium from 22.1 °C to 39.4 °C ?
Rainbow [258]

Answer:

Q = 2640.96 J

Explanation:

Given data:

Mass of He gas = 10.7 g

Initial temperature = 22.1°C

Final temperature = 39.4°C

Heat absorbed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree. Specific heat capacity of He is 14.267 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 39.4°C - 22.1°C

ΔT = 17.3°C

Q = 10.7 g× 14.267 J/g.°C ×  17.3°C

Q = 2640.96 J

5 0
3 years ago
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