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4 years ago

What carbon atoms can bond with

1 answer:

8 0

Carbon has four valence electrons, so it can achieve a full outer energy level by forming four covalent bonds. When it bonds only with hydrogen, it formscompounds called hydrocarbons. Carbon can form single, double, or triple covalent bonds with other carbon atoms.

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Which is true regarding the density of air?

Dima020 [189]

Warm air rises, cool falls. (a)

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3 years ago

Henry mixed salt and water together in a cup until he observed a clear solution. He measured the mass of the solution. Then he p

Svet_ta [14]

Statement 2 is correct.
solids moving into solution is a physical change as the core structure of the molecules remain the same. evaporation of water and crystallization of salt are both physical changes as well.
The water does not change it's H2O chemical makeup because salt was dissolved into it.

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4 years ago

Read 3 more answers

Quiero saber Que es un isótopo?

Kamila [148]

Son átomos que tienen el mismo número atómico, pero diferente masa atómica. Es decir, contienen el mismo número de protones pero difieren en el número de neutrones. Como ejemplo, tendríamos el Hidrógeno y sus 3 isótopos, el Protio, el Deuterio y el Tritio.

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3 years ago

How can you force a solid compound to the bottom of a melting point capillary? a. tap the closed endb. tap the open endc. use a

snow_lady [41]

Answer: option A. tap the closed end

Explanation:

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3 years ago

References Use the References to access important values if needed for this question A student ran the following reaction in the

ANTONII [103]

Answer:

19.27

Explanation:

Some values are corrected from correct source.Thus,

Moles of SO₂ = 8.19x10⁻² moles

Moles of O₂ = 8.10x10⁻² moles

Volume = 1 L

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Concentration of SO₂ = 8.19x10² M

Concentration of O₂ = 8.10x10 M

Considering the ICE table for the equilibrium as:

2SO₂ (g) + O₂ (g) ⇔ 2SO₃ (g)

t = o 8.19x10⁻² 8.19x10⁻²

t = eq -2x -x 2x

--------------------------------------------- --------------------------

neq: 8.19x10⁻² -2x 8.19x10⁻² -x 2x

Given:

Equilibrium concentration of O₂ = 5.98x10⁻² M = 8.19x10⁻² -x

Thus, x = 0.0212 M

[SO₂] = 8.19x10⁻² - 2*0.0212 = 0.0395 M

[SO₃] = 2*0.0212 = 0.0424 M

The expression for the equilibrium constant is:

$K_c=\frac {[SO_3]^2}{[SO_2]^2[O_2]}$

$K_c=\frac{{0.0424}^2}{{0.0395}^2\times 0.0598}$

K = 19.27

4 0

3 years ago