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lora16 [44]
3 years ago
13

1.

Chemistry
1 answer:
dedylja [7]3 years ago
7 0

Answer:

It looked like the continents fit together like puzzle pieces

Could I Maybee get brainlest if someone else answers?

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The reaction of sulfuric acid (H2SO4) with potassium hydroxide (KOH) is described by the equation below. Suppose 0.05 L of KOH w
strojnjashka [21]

From the chemical equation given:

H2SO4+2KOH--->K2SO4+2H2O

the two reactants, H2SO4 and KOH, are in 1:2 stoichiometric ratio.

No. of moles of KOH = 2* no. of moles of H2SO4

=2*0.1*0.033

The concentration of KOH = no. of moles / volume

=2*0.1*0.033/0.05

=0.132M

3 0
3 years ago
Read 2 more answers
Two Carnot engines are operated in series with the exhaust (heat output) of the first engine being the input of the second engin
OlgaM077 [116]

Answer:

(a) 140 F

(b) The temperature rise at the point where the heat is dumped is 2.51 degC

Explanation:

(a) Considering T1 the temperature of input of the first engine, T2 the temperature of the exhaust of the first engine (and input of the second engine) and T3 the exhaust of the second engine, if both engines have the same efficiency we have:

\eta=1-\frac{T_1}{T2}=1-\frac{T_2}{T_3}

The temperatures have to be expressed in Rankine (or Kelvin) degrees

1-\frac{T_1}{T2}=1-\frac{T_2}{T_3}\\\\\frac{T_1}{T2}=\frac{T_2}{T_3}\\\\(T_2)^{2} =T_1*T_3\\\\T_2=\sqrt{T_1*T_3} =\sqrt{(459.67+260)*(459.67+40)}= \sqrt{719.67*499.67}\\\\ T_2=599 \, R= (599-459.67) ^{\circ} F=140^{\circ} F

(b) The Carnot efficiency of the cycle is

\eta_{c}=1-Th/Ts=1-(273+20)/(273+315)=0.502

If the efficiency of the plant is 60% of the Carnot efficiency, we have

\eta=0.6*\eta_{c}=0.6*0.502=0.302

The heat used in the plant can be calculated as

Q_i=W/\eta=750MW/0.302=2483MW

And the heat removed to the heat sink is

Q_o=Qi-W=2483-750=1733MW

If the flow of the river is 165 m3/s, the heat per volume in the sink is

\frac{Q_o}{f} =\frac{1733 MJ/s}{165 m3/s}= 10.5MJ/m3

Considering a heat capacity of water C=4.1796 kJ/(kg*K) and a density ρ of 1000 kg/m3, the temperature rise of the water is

\Delta Q=C*\Delta T\\\Delta T=(1/C)*\Delta Q\\\Delta T=(\frac{1}{4.1796\frac{kJ}{kgK} } )*10,500\frac{kJ}{m3}*\frac{1m3}{1000kg}\\\Delta T= 2.51 ^{\circ}C

8 0
4 years ago
What are the factors that affect the rate of dissolution?
Liula [17]

Option (C) is the correct answer.

When solute is added to the solvent, results in the formation of solution and the process is said to be dissolution.

Dissolution process depends upon the three factors: temperature, stirring and surface area.

Stirring increases the rate of dissolving as when stirring a solute in the solvent, stirring helps in the distribution of solute throughout the solvent which results in speed up the dissolving rate.

Dissolution also depends upon the temperature, in warm solvent, solute dissolves readily whereas in cool solvent, solute dissolves slowly as particles have more movement energy.

Greater the surface area, there will be more contact between the solute particles and solvent particles which increases the rate of dissolving. Smaller the surface are, there will be less contact between the particles which decreases the rate of dissolving. For example: granulated sugar dissolves more readily due to larger surface area and one ice cube dissolves slowly due to smaller surface area.

Hence, rate of dissolution depends upon temperature, stirring, surface area.

4 0
3 years ago
Would anyone help <br> !!!!!
balu736 [363]

Answer

Explanation:

Protons would be the first answer since protons have a + charge. Neutrons would be second sicne neutrons have a neutral or 0 charge. Electrons would be the last since electrons have a - charge.

4 0
4 years ago
Read 2 more answers
Which of these is a chemical property?
ankoles [38]

Answer:

The second choice, or flammability.

Explanation:

The flammability of something is how easy it is for it to burn or ignite.

7 0
4 years ago
Read 2 more answers
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