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pochemuha
2 years ago
10

What is the representative particle for an element?

Chemistry
1 answer:
xz_007 [3.2K]2 years ago
3 0

Answer:

The representative particle for an element is AN ATOM.

Explanation:

Representative particle of a substance refers to the smallest unit of that substance, which can not be broken down into smaller particles. The representative particles of an element is an atom, because each element is made up of atoms, which are the smallest unit of that element; they can not be broken down further.

A representative particle is chemically identical with the parent element and will have all the properties of the parent element.  

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Not all of the water falls as rain, snow,or sleet evaporates. What happens to the rest of the water?
Bumek [7]
Hi there! All of the water returns to the atmosphere, it's called evapotranspiration and condenses. And then the water falls back to the Earth's surface and starts the cycle all over again. If you don't know what I mean, it's the Water Cycle.
4 0
3 years ago
You have decided to bake a cake. You mix all of your ingredients together to make a delicious chocolate cake. Then, you bake you
Lapatulllka [165]

Answer:

A gas is evolved

The ingredients can not be recovered

Explanation:

A chemical change is one in which a new substance is formed and it is not easily reversible.

One major ingredient used in cake baking is the baking powder or baking soda.

Baking a cake can be viewed as a chemical change. This is because, when the baking powder or soda is added in the presence of yeast, carbon dioxide gas is evolved as tiny bubbles of gas which makes the cake light and fluffy. Heat is equally given off in the process. The baking powder and other cake ingredients can not be recovered, hence, we can conclusively assert that a chemical change has taken place.

3 0
3 years ago
Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution in Fe for concentrations up to
Bess [88]

Answer:

Explanation:

To find the concentration; let's first compute the average density and the average atomic weight.

For the average density \rho_{avg}; we have:

\rho_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }

The average atomic weight is:

A_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }

So; in terms of vanadium, the Concentration of iron is:

C_{Fe} = 100 - C_v

From a unit cell volume V_c

V_c = \dfrac{n A_{avc}}{\rho_{avc} N_A}

where;

N_A = number of Avogadro constant.

SO; replacing V_c with a^3 ; \rho_{avg} with \dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} } ; A_{avg} with \dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} } and

C_{Fe} with 100-C_v

Then:

a^3 = \dfrac   { n \Big (\dfrac{100}{[(100-C_v)/A_{Fe} ] + [C_v/A_v]} \Big) }    {N_A\Big (\dfrac{100}{[(100-C_v)/\rho_{Fe} ] + [C_v/\rho_v]} \Big)  }

a^3 = \dfrac   { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100-C_v)A_{v} ] + [C_v/A_Fe]} \Big) }    {N_A  \Big (\dfrac{100 \times \rho_{Fe} \times  \rho_v }{[(100-C_v)/\rho_{v} ] + [C_v \rho_{Fe}]} \Big)  }

a^3 = \dfrac   { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100A_{v}-C_vA_{v}) ] + [C_vA_Fe]} \Big) }    {N_A  \Big (\dfrac{100 \times \rho_{Fe} \times  \rho_v }{[(100\rho_{v} - C_v \rho_{v}) ] + [C_v \rho_{Fe}]} \Big)  }

Replacing the values; we have:

(0.289 \times 10^{-7} \ cm)^3 = \dfrac{2 \ atoms/unit \ cell}{6.023 \times 10^{23}} \dfrac{ \dfrac{100 (50.94 \g/mol) (55.84(g/mol)} { 100(50.94 \ g/mol) - C_v(50.94 \ g/mol) + C_v (55.84 \ g/mol)   }   }{ \dfrac{100 (7.84 \ g/cm^3) (6.0 \ g/cm^3 } { 100(6.0 \ g/cm^3) - C_v(6.0 \ g/cm^3) + C_v (7.84 \ g/cm^3)   } }

2.41 \times 10^{-23} = \dfrac{2}{6.023 \times 10^{23} }  \dfrac{ \dfrac{100 *50*55.84}{100*50.94 -50.94 C_v +55.84 C_v} }{\dfrac{100 * 7.84 *6}{600-6C_v +7.84 C_v} }

2.41 \times 10^{-23} (\dfrac{4704}{600+1.84 C_v})=3.2 \times 10^{-24} ( \dfrac{284448.96}{5094 +4.9 C_v})

\mathbf{C_v = 9.1 \ wt\%}

4 0
2 years ago
Construct a three-step synthesis of trans-2-pentene from acetylene by dragging the appropriate formulas into the bins. Note that
Aleks [24]

Answer:

The three-step synthesis of trans-2-pentene from acetylene is as follows.

<u>Step -1:</u> Formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkanes.

<u>Step -2:</u> Formation terminal alkyne to nonterminal alkynes.

<u>Step -3:</u> Formation of trans-pent - 2-pent-ene by reduction.

Explanation:

Synthesis of trans-pent-2-yne from ethyne takes place is mainly a three step synthesis which involves formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkane. Second step involves the further alkylation of terminal alkynes to higher order nonterminal alkynes and the third step involves the formation of trans-2-ene by dissolving reduction method.

The chemical reaction of each step of chemical reactions is as follows.

7 0
2 years ago
A sample of pure alumina hydrate was obtained. A 5.000 g sample of the material was heated carefully in a vacuum oven until no m
lapo4ka [179]

Answer: The formula of the hydrated alumina is  Al_2O_3.5H_2O

Explanation:

Decomposition of hydrated alumina is given by:

Al_2O_3.xH_2O\rightarrow Al_2O_3+xH_2O&#10;

Molar mass of Al_2O_3 = 101.96 g/mol

According to stoichiometry:

(101.96+18x) g of  Al_2O_3.xH_2O decomposes to give 101.96 g of

Al_2O_3

Thus 5.000 g of   Al_2O_3.xH_2O decomposes to give=\frac {101.96}{(101.96+18x)}\times 5.000 of H_2O

But it is given 5.000 g of a sample of hydrated salt Al_2O_3.xH_2O was found to contain 2.6763 g of unhydrated salt

Thus we can equate the two equations:

\frac{101.96}{(101.96+18x)}\times 5.000=2.6763

x=5

Thus the formula of the hydrated alumina is  Al_2O_3.5H_2O

6 0
3 years ago
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