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lawyer [7]
3 years ago
5

A hydrate of CoCl2 has a mass of 15.80 g before heating. After heating the mass of the anhydrous compound is found to be 9.32 g

explain how you would determine the formula of the hydrate and then write out the full name of the hydrate
Chemistry
1 answer:
elixir [45]3 years ago
5 0

Explanation:

Molar mass of Cobalt (II) chloride = 129.8g/mol

Moles of CoCl2 = 9.32/129.8 = 0.0718mol

Mass of H2O lost after heating = 15.80 - 9.32 = 6.48g

Moles of H2O = 6.48/18 = 0.36mol

Mole ratio of CoCl2 : H20

= 0.0718mol : 0.36mol

= 1 : 5

Hence the formula is CoCl2 . 5H2O, which is Copper (II) chloride pentahydrate.

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When a saturated solution of NH4Br dissolved in 100 grams of water is cooled from 60°C to 30°C, how much NH4Br will precipitate?
stepladder [879]

Answer:

m_{precipitated}=24.8g

Explanation:

Hello,

In this case, since at 60 °C, 108 grams of ammonium bromide are completely dissolved in 100 grams of water for a saturated solution, once it is cooled to 30 °C, wherein only 83.2 grams are completely dissolved in 100 grams of water, the following mass will precipitate:

m_{precipitated}=108g-83.2g\\\\m_{precipitated}=24.8g

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What type of bonding occurs in a sample of pure chromium, cr? in other words, how is one chromium atom held to another chromium
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2 years ago
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Hope this answers the question.
5 0
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Read 2 more answers
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