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Naya [18.7K]
3 years ago
13

A bakery has d dozen eggs in one refrigerator and 3 fewer dozen eggs in another refrigerator. Which expressions correctly show h

ow many dozen eggs the bakery has in both refrigerators?
Mathematics
2 answers:
san4es73 [151]3 years ago
3 0

Answer:  2 d - 3

Step-by-step explanation:

Here, the number of dozen eggs in one refrigerator = d

According to the question,

There are 3 fewer dozen eggs in another refrigerator.

⇒ The number of eggs in another refrigerator = d - 3

Thus, the total dozen of eggs in both refrigerator = the number of dozen eggs in first refrigerator + the number of dozen eggs in second refrigerator

= d + d - 3

= 2 d - 3

Which is the required expression.

denis-greek [22]3 years ago
3 0

Answer:

d+d-3

2d-3

Step-by-step explanation:

There are 2 refrigerators and 3 fewer dozen eggs!

2d-3=d+d-3

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Write an equation of cosine function with amplitude 2 and a period 4pi
Arisa [49]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}

now.. hmmm let's see, keeping in mind the template above

so, amplitude of 2, A=2, thus |A| = ±2, so, you can use either

and period of 4π, well, that simply means that 

\bf \cfrac{2\pi }{B}=4\pi \implies \cfrac{2\pi }{4\pi }=B\implies \cfrac{1}{2}=B\\\\
-----------------------------\\\\

\begin{array}{llll}
f(\theta)=&\pm 2cos&\left(\frac{1}{2}\theta  \right)\\
&\ \uparrow &\ \uparrow \\
&A&B
\end{array}
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Answer:

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Step-by-step explanation:

3(2 + x)

Distribute

3*2 + 3*x

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