Explanation:
It is given that, a batter hits a pop-up to a fielder 93 m away, range of the projectile, R = 93 m
The ball remains in the air for 5.4 s, the time of flight is 5.4 s
Time of flight :
Maximum height of the projectile :
We need to find H.
So,
So, it will rise to a height of 35.72 m.
Answer:
Explanation:
Given that,
The Camden holds a volume of
V = 2,000,000 gallons
At a height of
h = 24 m
We want to find the potential energy.
And potential energy can be calculated using
P.E = mgh
Where
m is the mass
g Is the acceleration due to gravity
h Is the height.
Given that,
Then volume is
V = 2,000,000 gallons
From research.
1 gallon ≈ 3.785 kg
Then,
2,000,000 gallons = 2,000,000 × 3.785 kg
So,
P.E = mgh
P.E = 2,000,000 × 3.785 × 9.81 × 24
P.E = 1.782 × 10^9 J.
Answer:
the angle is about 67.79 degrees
Explanation:
We know that at its maximum height, the vertical component of the projectile's launching (initial) velocity (Vyi) is zero, so at that point it total velocity equals the horizontal component of the initial velocity (Vxi = 0.5 m/s)
We also know that the maximum height of the projectile is given by the square of its initial vertical component of the velocity (Vyi) divided by 2g, therefore half of such distance is :
we can use this information to find the y component of the velocity at that height via the formula:
Now we use the information that tells us the speed of the projectile at this height to be 1 m/s. That should be the result of the vector addition of the vertical and horizontal components:
Now we can use the arc-tangent to calculate the launching angle, since we know the two initial component of the velocity vector:
Answer:
We know that ΔK = Kf - Ki = 1/2 m Vf^2 - 1/2 m Vi^2 = 1/2m(Vf^2-Vi^2) = 1/2 m ΔV^2.
The mass remains the same, just calculate the difference of squared velocities and multiply it by half of the mass.
The time needed is 25 s
Explanation:
Assuming that the sprinter is moving by uniform motion, then we can use the following equation that relates distance, time and speed:
where
v is the speed of the sprinter
d is the distance covered
t is the time elapsed
In this problem, we know that
v = 4 m/s is the speed of the sprinter
d = 100 m is the distance that must be covered
Solving for t, we find the minimum time needed:
Learn more about speed:
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