Answer:
A battery produces _DC_ current, which is current that flows in only one direction.
Answer: D.
Explanation: Just took the quiz.
Answer:
The options are not shown, so let's derive the relationship.
For an object that is at a height H above the ground, and is not moving, the potential energy will be:
U = m*g*H
where m is the mass of the object, and g is the gravitational acceleration.
Now, the kinetic energy of an object can be written as:
K = (1/2)*m*v^2
where v is the velocity.
Now, when we drop the object, the potential energy begins to transform into kinetic energy, and by the conservation of the energy, by the moment that H is equal to zero (So the potential energy is zero) all the initial potential energy must now be converted into kinetic energy.
Uinitial = Kfinal.
m*g*H = (1/2)*m*v^2
v^2 = 2*g*H
v = √(2*g*H)
So we expressed the final velocity (the velocity at which the object impacts the ground) in terms of the height, H.
Answer:
110 yds
Explanation:
Well if 55 yards is 1/2 of the field then 2 x 55 = 110 yards is total field length
Answer:
![R = x_{max} = \frac{v^2\sin(2\theta)}{g}\\\frac{R_1}{R_2} = \frac{\sin(2\theta_1}{\sin(2\theta_2}](https://tex.z-dn.net/?f=R%20%3D%20x_%7Bmax%7D%20%3D%20%5Cfrac%7Bv%5E2%5Csin%282%5Ctheta%29%7D%7Bg%7D%5C%5C%5Cfrac%7BR_1%7D%7BR_2%7D%20%3D%20%5Cfrac%7B%5Csin%282%5Ctheta_1%7D%7B%5Csin%282%5Ctheta_2%7D)
Explanation:
Using kinematics equations:
![\Delta x = v_{0x}t\\\Delta y = -\frac{1}{2}gt^2+v_{0y}t](https://tex.z-dn.net/?f=%5CDelta%20x%20%3D%20v_%7B0x%7Dt%5C%5C%5CDelta%20y%20%3D%20-%5Cfrac%7B1%7D%7B2%7Dgt%5E2%2Bv_%7B0y%7Dt)
Use
due to condition of distance traveled.
Solving second equation for time, there are two solutions. t=0 and
![t=\frac{2v_{0y}}{g}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2v_%7B0y%7D%7D%7Bg%7D)
Use the expression in the first equation to have
![R = \frac{2v^2 \cos\theta\sin\theta}{g}](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7B2v%5E2%20%5Ccos%5Ctheta%5Csin%5Ctheta%7D%7Bg%7D)
Using trigonometric identities, you have the answer of the distance.
By doing the ratio for two different angles, you have the second answer. Due to sine function properties, the distances can be the same to complementary angles. Example, for 20° and 70°, the distance is the same.