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Marianna [84]
3 years ago
12

Which best compares a nondigital and a digital camera?

Physics
2 answers:
Fed [463]3 years ago
5 0
<h2>Answer:</h2>

<u>The correct statement is </u><u>A nondigital camera uses film to record images, and a digital camera uses sensors.</u>

<h2>Explanation:</h2>

A non digital camera uses a film and it works on the basis of light which is either produced by the flash light or sunlight. On the other hand a digital camera has its own sensors which has the ability to provide an option of low light compensation and it also allows the user to adjust the light controls digitally with the help of existing sensors.

masya89 [10]3 years ago
3 0
D. Digital cameras use sensors which detect the brightness and color of the light, while non-digital cameras project the light onto film, which develops over time.
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What is the impulse of a 1700 kg truck traveling at 22.5 m/s?
andrew-mc [135]
Impulse is just the product of mass and speed!

I = 1700 * 22.5  = 38,250 kg m/s

It does not have any special name for its units :(
3 0
3 years ago
Does electrons have more mass than neutrons?
musickatia [10]

Answer:

No, neutrons have about the same mass as a proton, but both have more mass than electrons.

Hope this helps a bit,

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3 0
3 years ago
The pressure inside a sealed container of methane gas (CH4) is 35.0 kPa. If this 80.0 L sample
STatiana [176]

Answer:

<h3>The answer is 30.43 L</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{35000 \times 80}{92000}  =  \frac{2800000}{92000}  =   \frac{700}{23}  \\  = 30.434782...

We have the final answer as

<h3>30.43 L</h3>

Hope this helps you

4 0
3 years ago
What is the mass of a 200 kg object on Venus?
saw5 [17]
A-200 kg
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8 0
3 years ago
Read 2 more answers
On a balanced seesaw, a boy three times as heavy as his partner sits
slega [8]

Answer:

1/3 the distance from the fulcrum

Explanation:

On a balanced seesaw, the torques around the fulcrum calculated on one side and on another side must be equal. This means that:

W_1 d_1 = W_2 d_2

where

W1 is the weight of the boy

d1 is its distance from the fulcrum

W2 is the weight of his partner

d2 is the distance of the partner from the fulcrum

In this problem, we know that the boy is three times as heavy as his partner, so

W_1 = 3 W_2

If we substitute this into the equation, we find:

(3 W_2) d_1 = W_2 d_2

and by simplifying:

3 d_1 = d_2\\d_1 = \frac{1}{3}d_2

which means that the boy sits at 1/3 the distance from the fulcrum.

8 0
3 years ago
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