Answer:
Tension in Cord=174 N
Explanation:
Given Data
L (Phone Cord Length)=4.89 m
m (Cord Mass)=0.212 Kg
T (Time for four trips)=0.617 s
Tension=?
Solution
V=λ×f



If the award weighs 200 newtons and 200 newtons equals 44.96 pounds of force even though it is of such a force if it hits the ground the energy will either discharge into the air doing nothing but creating a loud sound or it will discharge into the ground altering the ground that it landed on.
Hope this helps :)
Answer:
relative vorticity is -0.868 ×
s-1
Explanation:
given data
air parcel at latitude = 18◦N
relative vorticity = 5.8 × 10^−5 s−1
to find out
relative vorticity
solution
we will apply here conservation of vorticity that is
ζ + f = constant
we know ζ initial = 2Ωsin(5π/18)
and f initial = 5.8 ×
and f final = 2Ωsin(π/18)
and here angular frequency Ω = 0.7272 ×
s-1
its mean
ζ initial - ζ final = f final - f initial
so
ζ final = ζ initial - f final + f initial
ζ final = - 2Ωsin(5π/18) + ( 2Ωsin(π/18) + 5.8 ×
)
ζ final = - 2(0.7272 ×
) sin(5π/18) + ( 2(0.7272 ×
)sin(π/18) + 5.8 ×
)
ζ final = -0.868 ×
s-1
so relative vorticity is -0.868 ×
s-1
Answer:
15 m
Explanation:
Given,
Mass ( m ) = 75 kg
Potential energy ( P.E ) = 11,025 J
To find : Hight ( h )
Formula : -
P.E = mgh
[ Note : The value of g = 9.8 m/s² ]
h = P.E / mg
= 11,025 / ( 75 x 9.8 )
= 11,025 / 735
h = 15 m
Hence,
15 m is the high off the ground must you be if you mass is 75 kg and you have 11,025 J of energy stored inside.