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Ray Of Light [21]
3 years ago
9

i like honey but when u put it on your feet it sticks to the ground. how do i avoid the stickyness of honey when i want to clean

my floors with it
Physics
2 answers:
Gre4nikov [31]3 years ago
6 0

Answer:

please stop asking questions

Explanation:

loris [4]3 years ago
3 0
I don’t know, sorry
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A small asteroid of mass M is near a big asteroid of mass 3M. There are no other gravitating objects nearby. The magnitudes of t
spin [16.1K]

Answer:

Ratio of aBig to aSmall = 1 : 3

Explanation:

Detailed explanation and calculation is shown in the image below

7 0
4 years ago
01. Um carrinho de massa 10 kg é empurrado, horizontalmente, sobre uma superfície plana horizontal, com força constante de 20 N.
Lostsunrise [7]

Responder:

<h2>D. 1.5m / s² </h2>

Explicación:

Usaremos la segunda ley de movimiento de Newton para resolver esta pregunta. De acuerdo con el teorema

es la suma de las fuerzas que actúan sobre el cuerpo a lo largo de la horizontal. Las dos fuerzas son la fuerza móvil (Fm) y la fuerza de fricción (Ff).

Fm = 20 N y Ff = 5 N

\sum Fx = ma_x\\\sum Fx = Fm - Ff\\\sum Fx  = 20N - 5N\\\sum Fx  = 15N

m es la masa del cuerpo = 10 kg

El parámetro requerido es cuál es la aceleración del cuerpo a lo largo de la horizontal.

De la ecuación 1;

a_x = \sum Fx/m\\\\a_x = 15/10\\\\a_x = 1.5m/s^2

Por lo tanto, la aceleración del carro es de 1.5 m / s²

3 0
4 years ago
Two children weighing 17 and 25 kilograms are sitting on opposite sides of a seesaw, both 2 meters from the axis of rotation. wh
Over [174]
The principle of moments states that for a system at equilibrium the clockwise moments is equal to the anticlockwise moments.
Moments is given by force × perpendicular distance
Moments one one side of the seesaw will be 340Nm and on the other will be 500Nm, for balanced or equilibrium to be achieved the two moments should be equal.
Difference is 160 Nm, thus with a child 10 kg to balance the system, then,
Distance will be 16 nm/ 100N = 1.6 m
Threfore, a child of 10 kg should sit at a  distance of 1.6m from the pivot on the side with 17 kg child for the system to balance.
8 0
4 years ago
"if the left-hand mass is 2.3 kg ,what should the right-hand mass be so that it accelerates downslope at 0.64 m/s2?"
VARVARA [1.3K]

m₁ = 2.3 kg <span>
θ₁ = 70° </span><span>
θ₂ = 17° </span><span>
g = 9.8 m/s² 

->The component of the gravitational force on m₁ that is parallel down the incline is: </span><span>
F₁ = m₁ × g × sin(θ₁) </span><span>
F₁ = (2.3 kg) × (9.8 m/s²) × sin(70°) = 21.18 N </span><span>

->The component of the gravitational force on m₂ that is parallel down the incline is: </span><span>
F₂ = m₂ × g × sin(θ₂) </span><span>
F₂ = m₂ × (9.8 m/s²) × sin(70°) = m₂ × (2.86 m/s²) </span><span>

Then the total mass of the system is: 
m = m₁ + m₂ </span><span>
m = (2.3 kg) + m₂ </span><span>

If it is given that m₂ slides down the incline, then F₂ must be bigger than F₁, </span><span>
and so the net force on the system must be: 
F = m₂×(2.86 m/s²) - (21.18 N) </span><span>

Using Newton's second law, we know that 
F = m × a 
So if we want the acceleration to be 0.64 m/s², then 
m₂×(2.86 m/s²) - (21.18 N) = [(2.3 kg) + m₂] × (0.64 m/s²) </span><span>
m₂×(2.86 m/s²) - (21.18 N) = (1.47 N) + m₂×(0.64 m/s²) </span><span>
m₂×(2.22 m/s²) = (22.65 N) </span><span>
m₂<span> = 10.2 kg</span></span>

5 0
4 years ago
The scale on the horizontal axis is 8 s per division and on the vertical axis 5 m per division. What is the time represented by
Nadya [2.5K]

Answer:

24 s

Explanation:

8 s / tic    *    3 tic = 24 sec from origin

8 0
2 years ago
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