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Tatiana [17]
3 years ago
7

The portion of the sailboat outlined in this photo closely resembles a(n)

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
4 0

Answer:

B

Step-by-step explanation:

The solution is right triangle. The triangle appears to have one right angle and two acute angles. This fits the definition of a right triangle.

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Whats the y intercept of y=4x -3
AleksAgata [21]

Answer:

-3

Step-by-step explanation:

the y intercept is the number that does not have a variable behind it (3)

the slope is the number that does have a variable behind it (4)

6 0
2 years ago
Read 2 more answers
What is csc ( Reduce fractional answers to lowest terms.
harina [27]

Answer:

cscA = \frac{5}{4}

Step-by-step explanation:

Using the identity

csc x = \frac{1}{sinx} , then

sinA = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{8}{10} = \frac{4}{5} , thus

cscA = \frac{1}{\frac{4}{5} } = \frac{5}{4}

4 0
3 years ago
Two of the 240 passengers are chosen at random. Find the probability that
hjlf

Step-by-step explanation:

there are in total 240 passengers.

out of these 240, there are 150+30=180 passengers that are in holiday.

and 240-180 = 60 passengers are not.

if we pick one passenger then the probability is 180/240 = 3/4 = 0.75 that he/she is on holiday.

remember : desired "events" over total "events".

i)

now we pick 2 passengers.

the probabilty for the first one to be on holiday is again

3/4 or 0.75.

if that event happens, then we have only 179 passengers out of now 239 to be on holiday.

and to pick one out of that pool to be on holiday is then

179/239 = 0.748953975...

and for both events to happen in one scenario we need to multiply both probabilities (it is an "and" relation, while an addition would be for an "exclusive or" relation).

the probabilty that we pick 2 passengers on holiday is

3/4 × 179/239 = 0.561715481... ≈ 0.5617

we cannot simply square the basic probability of 0.75 (0.75² = 0.5625), because that would mean we pick one passenger, then put him back into the crowd, and then pick a second time (with a chance to pick the same person again). like with rolling a die.

but that is not the scenario as I understand it. it is to pick a passenger, then keep that person singled out and pick a second passenger. hence the difference.

ii)

exactly one of the two is in holiday.

that means

either the first one is on holiday and the second one is not, or the the second one is and the first one is not.

now we model this logic statement in probabilty arithmetic.

please note that after the first pull we need to update the numbers for the remaining pool depending on the result of the first pull.

the total remaining is in both cases 239. but either the remaining people on holiday go down to 179 (and not in holiday stays 60), or the remaining people not on holiday go down to 59 (and on holiday stays 180).

so, the first one is on holiday, and the second one is not :

3/4 × 60/239 (remember : "and" relation)

= 3 × 15/239 = 45/239 = 0.188284519...

the first one is not on holiday, and the second one is :

60/240 × 180/239 = 1/4 × 180/239 = 45/239 =

= 0.188284519...

since there is no overlap of the potential events (there is no event that could be in both cases), this is an exclusive or relation, and we can add the probabilities.

so, the probability for exactly one of the picked passengers to be on holiday is

2×0.188284519... = 0.376569038... ≈ 0.3766

8 0
2 years ago
Gary wants to buy a video game with a selling price of $48, on sale for 50% off. The sales tax in his state is 4.5%. How much wi
Anna [14]

Answer:

$25.20

Step-by-step explanation:

First, take the 50% off the sales price:

($48)*(-0.50) = -$24.

($48 - $24) = $24 sale price.

Tax on $24 is ($24)*(0.05) = $1.20

Add the price and sales tax:

$24 + $1.20 = $25.20

5 0
2 years ago
There is a bag filled with 4 blue and 5 red marbles.
Elan Coil [88]
4/9 (4 out of 9) because you add them all together then count the number of blue marbles then since you put back the first marble, the dominator is still the same
3 0
3 years ago
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