Answer:
144
Step-by-step explanation:
The series is described by the problem statement as ...
... 0 +4 +8 +12 +... +32
= 4*(0 +1 +2 +... +8) . . . . . the first 9 multiples of 4, starting with 0
Now we know the sum of integers 1..n is given by n(n+1)/2. So for n=8, this is ...
... 8·9/2 = 36
Multiplying this by 4, we find the series sum to be ...
= 4·(sum of integers 0 .. 8) = 4·36 = 144
_____
<em>Comment on the answer choices</em>
It appears your answer choices may not include the value 144. That is unfortunate. You may want to <em>ask your teacher to show you how to work this problem</em> and reconcile the answer choices with the problem statement.
The 9-term series <u><em>starting with 4</em></u> will have sum ...
... 4·(1 +2 +3 +... +9) = 4·(9·10)/2 = 4·45 = <em>180</em>