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kkurt [141]
3 years ago
5

What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0
The answer is 
x=18,-2

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Okay I’ve been struggling on this for like 20 min, someone Pleaseee help me
Debora [2.8K]

Answer:

Angle M=14.25°

Step-by-step explanation:

Sin(M)=16/65

Sin^-1(16/65)=14.25°

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3 years ago
Mckenzie has been saving her earnings from mowing the
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Answer:

7 games

Step-by-step explanation:

22 / 3 =

7.33

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2 years ago
Modeling the number of transport bus breakdowns in every month to determine if an additional bus should be purchased. The runnin
skelet666 [1.2K]

Answer:

The probability of exactly 2 breakdowns next month = 0.08422

Step-by-step explanation:

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6 0
3 years ago
Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621​
REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

a=-6

T_n=58

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here a_1=-6\ and\ a_2=-5

\therefore d=a_2-a_1=-5-(-6)=-5+6=1

Now we use the formula of A.P.

T_n=a+(n-1)d

On substituting the values, we get;

58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65

So there are 65 terms in between  -6 To 58.

That means we have to find the sum of 65 terms in between  -6 To 58.

Now we use the formula of Sum of n_terms.

S_n=\frac{n}{2}(2a-(n-1)d)

On substituting the values, we get;

S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

5 0
3 years ago
What is the density of sample 3, if the Mass(g) was 5 1/4 and the Volume(mL) was 16.9?
iogann1982 [59]
5 1/4 divided by 16.9 is 0.31
8 0
3 years ago
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