Answer:
The options are not shown, so i will answer in a general way.
Let's define the variables:
h = number of hats
m = number of mugs.
We know that a total of 1000 items were ordered, then:
h + m = 1000
We also know that we have 3 times more mugs than hats, this can be written as:
m = 3*h
Now we have the system of equations:
h + m = 1000
m = 3*h
To solve these, we usually start by isolating one of the variables in one equation and then replace that in the other equation, but in this case, we already have m isolated in the second equation, then we can replace that in the first equation to get:
h + m = 1000
h + (3*h) = 1000
Now we can solve this equation for h, and find the number of hats ordered.
4*h = 1000
h = 1000/4 = 250
There were 250 hats ordered.
Whole package weighs 20pounds
1.65 = 5pounds
0.12 = extra pound
3.45 - 1.65 = 1.80 : 0.12 = 15pounds
Adding up 15pounds and the first 5 pounds equal 20 pounds
Answer:
HOPE THIS HELPS!!
Step-by-step explanation:
YOU could find it by doing these steps:
Atual Area = ���� square units.
Scale Drawing Area = �� square units.
Value of the Ratio of the Scale Drawing Area to the Actual Area:
Answer:
See explanation
Step-by-step explanation:
Given 
According to the order of the vertices,
- side AB in triangle ABC (the first and the second vertices) is congruent to side AD in triangle ADC (the first and the second vertices);
- side BC in triangle ABC (the second and the third vertices) is congruent to side DC in triangle ADC (the second and the third vertices);
- side AC in triangle ABC (the first and the third vertices) is congruent to side AC in triangle ADC (the first and the third vertices);
- angle BAC in triangle ABC is congruent to angle DAC in triangle ADC (the first vertex in each triangle is in the middle when naming the angles);
- angle ABC in triangle ABC is congruent to angle ADC in triangle ADC (the second vertex in each triangle is in the middle when naming the angles);
- angle BCA in triangle ABC is congruent to angle DCA in triangle ADC (the third vertex in each triangle is in the middle when naming the angles);
