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Nataly_w [17]
3 years ago
15

HELP ME ITS FOR 20 POINTS

Mathematics
2 answers:
Bogdan [553]3 years ago
8 0
I’m so sorry I it’s wrong but imma say it’s 30 gallons as well
tangare [24]3 years ago
7 0

Answer:

Ans is 30.................

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When a certain kind of bacterium takes a step, it moves 3 x 10^-7 meters. When
mixas84 [53]

Answer:

Step-by-step explanation:

0.75/(3*10^(-7)) = 0.25*10^7 = 2.5*10^6

3 0
3 years ago
Suppose Randolph decides that the radius of his pool will be 50 meters. What volume of water, in cubic meters, will be needed to
tangare [24]
If we assume the pool to be a semi sphere,  then the volume would be
<span>
V pool = 1/2 * [4/3*pi*r**(3)]

</span>where r is the radius = 50m

V pool = 1/2 * [4/3*3.14*50**(3)]
<span>
V pool =
261799.3878 m</span>³

If we round up >>> V water in the pool = 261800 m
³<span>


</span>
8 0
3 years ago
PLZ HELP I NEED BY 2:00 PM ATY LEAST!!! WILL GIVE BRAINLYIST<br> Find the value of in each case:
Pie

Answer:

23°

Step-by-step explanation:

Step 1:

< GEC + < ECG + < CGE = Δ ECG    Sum of a Δ

Step 2:

< IGF = < GCE    Corresponding ∠ 's

Step 3:

14° + 180° - 4x + 78° = 180°   Substitution

Step 4:

272° - 4x = 180°     Add / Algebra

Step 5:

- 4x = - 92   Subtract 272° on both sides

Step 6:

- 92 ÷ - 4   Divide

Answer:

x = 23°

Hope This Helps :)

7 0
3 years ago
Read 2 more answers
A small craft in lake Ontario sends out a distances signal. The coordinates of the boat in trouble are (57,64). One rescue boat
KatRina [158]

Answer:

The coast guard craft will get to the distressed boat the fastest.

Step-by-step explanation:

The coordinates of boat are (57,64).

The coordinates of rescue boat are (67,83).

The  coordinates of coast guard craft are (65,46).

Both rescue crafts travel at the same rate. One of them will get to the distressed boat the faster, whose distance from the boat is least.

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The distance between boat and rescue boat is

d_1=\sqrt{(67-57)^2+(83-64)^2}=21.4709105536\approx 21.47

The distance between boat and coast guard craft is

d_2=\sqrt{(65-57)^2+(46-64)^2}=19.6977156036\approx 19.70

Since the distance between boat and coast guard craft is least, therefore coast guard craft will get to the distressed boat the fastest.

6 0
3 years ago
In the figure, x ǁ y and a ǁ b.<br><br> What is m∠5?<br><br> m∠5 = °
Katena32 [7]
M∠1 =m∠2 =m∠3=<span><span><span>m∠4=</span>180-58=122°
</span>m∠5 = 58°</span>





6 0
3 years ago
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