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Kipish [7]
3 years ago
10

In a right triangle, angle C measures 40°. The hypotenuse of the triangle is 10 inches long. What is the approximate length of t

he side adjacent to angle C?

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

<em>Approximate length of the side adjacent to ∠C is </em><em>7.66 inches.</em>

Step-by-step explanation:

*The appropriate triangle is attached below.

From the diagram, the right triangle ABC has

  1. Hypotenuse = \overline{AC}=10\ inch
  2. m\angle C=40^{\circ}

The side adjacent to angle C is BC. We can get the length of BC by applying trigonometric operations.

We know that,

\cos \theta =\dfrac{b}{h}

Putting the values,

\Rightarrow \cos 40 =\dfrac{BC}{10}

\Rightarrow BC=\cos 40 \times {10}

\Rightarrow BC=7.66\ in

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Angle 2 is half of 115 so it would be 57.5 and angle 1 would be 122.5 degrees
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Match each vertex in IJL to its corresponding vertex in the dashed triangle.
dimaraw [331]

Answer:

Step-by-step explanation:

It’s LJK

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3 years ago
. Let X and Y be random variables of possible percent returns (0%, 10%,
bazaltina [42]

(a) The marginal distribution of <em>X</em> is

Pr(<em>X</em> = <em>x</em>) = ∑ Pr(<em>X</em> = <em>x</em>, <em>Y</em> = <em>y</em>)

… = 0.0625 + 0.0625 + 0.0625 + 0.0625

… = 0.25

That is, the first equality follows from the law of total probability, with the sum taken over <em>y</em> from {0, 5, 10, 15}. Each probability Pr(<em>X</em> = <em>x</em>, <em>Y</em> = <em>y</em>) is given in the table to be 0.0625.

Similarly, the marginal distribution of <em>Y</em> is

Pr(<em>Y</em> = <em>y</em>) = 0.25

(b) Yes, they're independent because

Pr(<em>X</em> = <em>x</em>, <em>Y</em> = <em>y</em>) = 0.0625,

and

Pr(<em>X</em> = <em>x</em>) Pr(<em>Y</em> = <em>y</em>) = 0.25 • 0.25 = 0.0625.

(c) The mean of <em>X</em> is

E[<em>X</em>] = ∑ <em>x</em> Pr(<em>X</em> = <em>x</em>)

… = 0.25 ∑ <em>x</em>

<em>… </em>= 0.25 (0 + 5 + 10 + 15)

… = 7.5

and you would find the same mean for <em>Y</em>,

E[<em>Y</em>] = 7.5

The variance of <em>X</em> is

V[<em>X</em>] = E[<em>X</em>^2] - E[<em>X</em>]^2

… = (∑ <em>x</em>^2 Pr(<em>X</em> = <em>x</em>)) - 7.5^2

… = 0.25 (∑ <em>x</em>^2) - 56.25

… = 0.25 (0^2 + 5^2 + 10^2 + 15^2) - 56.25

… = 31.25

and similarly,

V[<em>Y</em>] = 31.25

(each sum is taken with <em>x</em> and <em>y</em> from {0, 5, 10, 15})

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Answer:

2. 2N

3. -4N

4. 4N

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Step-by-step explanation:

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9. A pet store has 45 mice. The number of mice is 22 more than the number of cats. Which equation can be solved to find the numb
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Answer

C. c+22=45

Working
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