<em>The moment of inertia of the system about an axis through the center of the square, perpendicular to the plane is </em><em>0.064 kg.m²</em>
<h3>Further explanation</h3>
<u><em>Complete Question:</em></u>
<em>Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods. Find the moment of inertia of the system about an axis through the center of the square, perpendicular to the plane!</em>
<u>Given:</u>
mass of sphere = m = 0.200 kg
length of side = x = 0.400 m
<u>Asked:</u>
net moment of inertia = ΣI = ?
<u>Solution:</u>
<em>Firstly , let's find distance between center of the square and the sphere:</em>
<em>Next , we could find total moment of inertia as follows:</em>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Circular Motion
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant