Answer:
The the maximum force acting on the crate is 533.12 newtons.
Explanation:
It is given that,
Mass of the wooden crate, m = 136 kg
The coefficient of static friction, 
The coefficient of kinetic friction, 
We need to find the maximum force exerted horizontally on the crate without moving it. As the crate is not moving than the coefficient of static friction will act and the force is given by :
F = 533.12 N
So, the maximum force acting on the crate is 533.12 newtons. Hence, this is the required solution.
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Answer:
The separation distance between the slits is 16710.32 nm.
Explanation:
Given that,
Wavelength = 641 nm
Angle =4.4°
(a). We need to calculate the separation distance between the slits
Using formula of young's double slit
Where, d = the separation distance between the slits
m = number of order
=wavelength
Put the value into the formula
Hence, The separation distance between the slits is 16710.32 nm.
Answer:
The tension in the rope is 20 N
Solution:
As per the question:
Mass of the object, M = 2 kg
Density of water, 
Density of the object, 
Acceleration due to gravity, g = 
Now,
From the fig.1:
'N' represents the Bouyant force and T represents tension in the rope.
Suppose, the volume of the block be V:
V = 
(1)
Also, we know that Bouyant force is given by:
Using eqn (1):
From the fig.1:
N = Mg + T
40 = 2(10) + T
T = 40 - 20 = 20 N
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