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Ierofanga [76]
2 years ago
14

17) The charge of an anti-charm quark isapproximately equal to

Physics
1 answer:
Gnom [1K]2 years ago
7 0

The charge of an anti-charm quark is approximately equal to  +5.33 ×10⁻²⁰ C.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

The charge on electron is equal to e = -1.6 x 10⁻¹⁹C

The charge of an anti- charm quark is +23 times the magnitude of charge on electron.

So, charge on  anti- charm quark is

q = +1/3 x ( 1.6 x 10⁻¹⁹C)

q =  +5.33 ×10⁻²⁰ C

Thus, the charge of an anti-charm quark is approximately equal to +5.33 ×10⁻²⁰ C.

Learn more about electrons.

brainly.com/question/1255220

#SPJ1

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Answer:

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How many atoms of oxygen are there in one molecule of trinitrotoluene, if the chemical formula is C6H3(NO2)3?
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2 x 3 = 6

Thus there are 6 atoms of oxygen in this molecule.

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An empty rubber balloon has a mass of 12.5 g. The balloon is filled with helium at a density of 0.181 kg/m3. At this density the
Eduardwww [97]

Answer: 1.14 N

Explanation :

As any body submerged in a fluid, it receives an upward force equal to the weight of the fluid removed by the body, which can be expressed as follows:

Fb = δair . Vb . g = 1.29 kg/m3 . 4/3 π (0.294)3  m3. 9.8 m/s2

Fb = 1.34 N

In the downward direction, we have 2 external forces acting upon the balloon: gravity and the tension in the line, which sum must be equal to the buoyant force, as the balloon is at rest.

We can get the gravity force as follows:

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The mass of helium can be calculated as the product of the density of the helium times the volume of the balloon (assumed to be a perfect sphere), as follows:

MHe = δHe . 4/3 π (0.294)3 m3 = 0.019 kg

Fg = (0.012 kg + 0.019 kg) . 9.8 m/s2 = 0.2 N

Equating both sides of Newton´s 2nd Law in the vertical direction:

T + Fg = Fb

T = Fb – Fg = 1.34 N – 0.2 N = 1.14 N

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2 years ago
Determine the minimum wavelength of light absorbed by (a) diamond, (b) gallium phosphide and (c) tin sulfide if the gap energies
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