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nadezda [96]
3 years ago
5

Mathematics and fractions 1/2 and 6/12

Mathematics
1 answer:
77julia77 [94]3 years ago
7 0

Answer:

Equivalent fractions

Step-by-step explanation:

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Vesna [10]
The lines mean that they are congruent! so the perimeter is 25*4 = 100
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I'm confused how do I simplify that??
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4(x-2)=4x-8 is this equation always true
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Yes, 4(x-2) is 4 times x-2 which using the distributive property gives you 4x-8 because 4 times x is 4x and 4 times -2 is -8 so you would always get 4x-8

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3 years ago
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Explain why Rolle's Theorem does not apply to the function even though there exist a and b such that f(a)
Anna35 [415]

Rolle's Theorem does not apply to the function because there are points on the interval (a,b) where f is not differentiable.

Given the function is f(x)=\sqrt{(2-x^{\frac{2}{3}})^{3}}  and the Rolle's Theorem does not apply to the function.

Rolle's theorem is used to determine if a function is continuous and also differentiable.

The condition for Rolle's theorem to be true as:

  • f(a)=f(b)
  • f(x) must be continuous in [a,b].
  • f(x) must be differentiable in (a,b).

To apply the Rolle’s Theorem we need to have function that is differentiable on the given open interval.

If we look closely at the given function we can see that the first derivative of the given function is:

\begin{aligned}f(x)&=\sqrt{(2-x^{\frac{2}{3}})^3}\\ f(x)&=(2-x^{\frac{2}{3}})^{\frac{3}{2}}\\ f'(x)&=\frac{3}{2}(2-x^{\frac{2}{3}})^{\frac{1}{2}}\cdot \frac{2}{3}\cdot (-x)^{\frac{1}{3}}\\ f'(x)&=\frac{-\sqrt{2-x^{\frac{2}{3}}}}{\sqrt[3]{x}}\end

From this point of view we can see that the given function is not defined for x=0.

Hence, all the assumptions are not satisfied we can reach a conclusion that we cannot apply the Rolle's Theorem.

Learn more about Rolle's Theorem from here brainly.com/question/12279222

#SPJ4

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2 years ago
Consider the linear function that is represented by the equation y = 2 x + 2 and the linear function that is represented by the
Arisa [49]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
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