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algol [13]
4 years ago
8

How are chemical formulas of binary ionic compounds generally written? a cation on left, anion on right b anion on left, cation

on right c roman numeral first, then anion, then cation d subscripts first, then ions?
Chemistry
2 answers:
guajiro [1.7K]4 years ago
8 0

Answer:  a cation on left, anion on right

Explanation: Binary ionic compounds are compounds formed by a metal and a non metal where a metal loses electron to form positively charged cation and the non metal gains electrons to form negatively charged anion.

The chemical formula of ionic compound is written by writing the cation first and then the anion.

For Example: Binary ionic compound sodium chloride is written as :

NaCl where sodium is present as cation (Na^+) and chlorine is present as anion (Cl^-)

Margarita [4]4 years ago
3 0
<span>a) cation on left, anion on right b anion on left, for example NaCl.</span>
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N2(g) + 2H(g) -&gt; N2 H4(g) What are the volumes of N2 gas and H2 gas required to form 28.5 grams of N2 H4 at 30'C and 1.50 atm
FromTheMoon [43]

Answer:

Volume of N₂ = 14.76 L

Volume of H₂ = 29.52 L

Explanation:

Given data:

Mass of N₂H₄ formed = 28.5 g

Pressure = 1.50 atm

Temperature = 30°C (30+273 = 303 k)

Volume of N₂ and H₂ needed = ?

Solution:

Chemical equation:

N₂ + 2H₂  →  N₂H₄

Number of moles of N₂H₄ formed = mass/ molar mass

Number of moles of N₂H₄ formed = 28.5 g/ 32 g/mol

Number of moles of N₂H₄ formed = 0.89 mol

Now we will compare the moles of N₂H₄ with N₂ and H₂ form balance chemical equation.

                N₂H₄                :                 N₂

                   1                     :                   1

                  0.89               :               0.89

                N₂H₄                :                 H₂

                   1                    :                  2

                 0.89               :                2×0.89 = 1.78 mol

Volume of H₂:

PV = nRT

1.50 atm × V = 1.78 mol × 0.0821 atm.L/mol.K × 303 K

V = 44.28atm.L /1.50 atm

V = 29.52 L

Volume of N₂:

PV = nRT

1.50 atm × V = 0.89 mol × 0.0821 atm.L/mol.K × 303 K

V = 22.14 atm.L /1.50 atm

V = 14.76 L

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