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balu736 [363]
3 years ago
7

When organic molecules are presented in simplified form, what should you place at each branch point?

Chemistry
2 answers:
trapecia [35]3 years ago
8 0

Answer:

Each branch point represents a CH moiety

Explanation:

  • Organic molecules in simplified form are drawn in skeleton formula.
  • In skeleton formula, only some lines are shown in zig zag manner. Intersection point between two lines represents CH_{2} moiety and each terminal end of a line represents CH_{3} moiety.
  • A branch is shown by a line too. The branch point represents a CH moiety and terminal end of branch represents a CH_{3} moiety.
  • For an example, consider an organic molecule 2-methyl propane.
  • Simplified structure is shown below.

mojhsa [17]3 years ago
4 0
To answer the questions above - The carbon and hydrogen atoms are taken out of the<span>figure when shown in simplified form. Each branch point represents a carbon atom 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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Answer: The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1

Explanation:

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According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Thus as oxygen and nitrogen are at same temperature and pressure and are in equal volume flasks , they have same number of moles and thus have same number of molecules.

The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1

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3 years ago
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<span>Be:[He]2<span>s2
</span></span><span>B:[He]2<span>s2</span>2<span>p1

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When you remove an electron from beryllium, you are taking away an electron from the 2s orbital. When you remove an electron from boron, you are taking an electron from the 2p orbital. The 2p electrons have more energy than the 2s, so it is easier to remove them as they can more strongly resist the effective nuclear charge of the nucleus.

7 0
4 years ago
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madreJ [45]
Hello!

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HSO₄⁻(aq) + H₂O(l) ⇄ SO₄⁻²(aq) + H₃O⁺(aq)

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Explanation:

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